How to change function name dynamically in python

Question

I want to change the function name according to result obtained from another function but the function definition remains same How can i do this i tried the following example but it didn't work

def f(text):
   def x(text):
     return text+"example"
   name=x(text)
   def name(y):
     return y
   return name
p=f("hi ")
print p("hello")
print p.__name__

OUTPUT

hello
name

But i want the function name p.__name__ as "hi example" not name

@esaelPsnoroMoN: can't speak for the OP, but personally I have done this to tailor documentation for closures, dynamically assigning __doc__ as well. A closure retains the internal name, which arguably should be encapsulated. — cdarke
– cdarke, Commented Sep 14, 2012 at 6:47

phihag · Accepted Answer · 2012-09-14 06:40:48Z

8

You can simply assign to __name__:

def f(text):
   def r(y):
     return y
   r.__name__ = text + "example"
   return r
p = f("hi ")
print (p("hello")) # Outputs "hello"
print (p.__name__) # Outputs "hi example"

Note that a function name does not have any influence on the function's behavior though, and does not have any meaning except as a part of the string representation or a debugging aid.

edited Sep 14, 2012 at 6:40

answered Sep 14, 2012 at 5:59

phihag

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2 Comments

Matthew Trevor Over a year ago

I'm not so sure __name__ is an implementation detail, it's listed as part of the data model.

phihag Over a year ago

@MatthewTrevor Oh, you're totally right - it's even declared writable. Fixed.

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