Finding the minimum and maximum in python

Are you allowed to use built-in functions of Python? If yes, it is easier:

number = raw_input('Enter number:')
list_of_numbers = number.split()

numbersInt = map(int, list_of_numbers) # convert string list to integer list

print("Size:",    len(numbersInt))
print("Min:",     min(numbersInt))
print("Max:",     max(numbersInt))
print("Sum:",     sum(numbersInt))
print("Average:", float(sum(numbersInt))/len(numbersInt) if len(numbersInt) > 0 else float('nan'))
# float conversion is only required by Python 2. 

where numbersInt = map(int, list_of_numbers) converts each string number of the list to an integer. Each function has the following meaning:

• len computes the length of a list
• min computes the minimum
• max computes the maximum
• sum computes the sum of a list

There isn't a mean function in Python standard library. But you can use numpy.mean() instead. Install it with pip install numpy or conda install numpy, then:

import numpy as np
print("Average: ", np.mean(numbersInt))

I think you can use min() and max() to find those values.

You have two options:

• You could compare the current number to the previous extrema and update your minimum and maximum accordingly;

  import sys
  tally = 0
  sum = 0
  nmax = -sys.maxint
  nmin = +sys.maxint
  number = raw_input('Enter number:')
  while number!= '':
      number = int(number)
      if number > nmax:
          nmax = number
      elif number < nmin:
          nmin = number
      tally = tally + 1
      sum += number
      average = float(sum) / float(tally)
      number = raw_input('Enter number:')
  

  We use the largest integer on your system (sys.maxint) to initialize our nmin and nmax

• You could store each number in a list, then perform all the operations at once:

  number = raw_input('Enter number:')
  numbers = []
  while number!= '':
      numbers.append(int(number))
      number = raw_input('Enter number:')
  numbers.sort()
  nmin = numbers[0]
  nmax = numbers[-1]
  tally = len(numbers)
  nsum = sum(numbers)
  avg = nsum/float(tally)
  

This may be with least complexity if I am not wrong.

len_min_max_sum=reduce(lambda x,y : (x[0]+1,y,x[2],x[3]+y) if x[0]>y else (x[0]+1,x[1],y,x[3]+y) if x[2]<y else (x[0]+1,x[1],x[2],x[3]+y) ,arr,(0,arr[0],arr[0],0))

len_min_max_sum_avg=(len_min_max_sum[0],len_min_max_sum[1],len_min_max_sum[2],len_min_max_sum[3],float(len_min_max_sum[3])/len_min_max_sum[0])

tally = 0
sum = 0
average = 0
while (True):
    number = input('Enter number')
    list_of_numbers = number.split()
    if number == '':
        continue
    else:
        tally = tally + 1
        sum = sum + int(number)
        average = float(sum)/float(tally)
    print('Size:', tally)
    print('Sum:', sum)
    print('Average:', average)

The max() and min() predefined math methods in python can solve this as below

numbers = [3,2,5,9,5,3]
minimum = min(numbers)
maximum = max(numbers)

result of the above is

>>>maximum
9
>>>minimum
2

Hope that helps.