PHP Unix timestamp

Question

I have a code but can't find where is an error. I have upcoming event and current time. If I convert my event to the timestamp it's less then current timestamp. May be you can help me.

My code below:

<?php

date_default_timezone_set('Etc/GMT');

$upcoming       = "2012.09.05 23:50";
$current        = time();

echo "Upcoming: " . $upcoming . " | Timestamp:" .  mktime(23, 50, 0, 09, 05, intval(date("Y")));
echo "<br>Current: " . time();
echo "<br>Current SIM: " .  mktime(date("H"), date("i"), date("s"), date("m"), date("d"), date("Y"));


?>

Will output:

Upcoming: 2012.09.05 23:50 | Timestamp:1323129000
Current: 1346855221
Current SIM: 1346855220

Where Current > Upcoming timestamp. (???) Thanks!

Yes. This string: date_default_timezone_set('Etc/GMT');

XTRUST.ORG
– XTRUST.ORG

2012-09-05 14:42:07 +00:00
Commented Sep 5, 2012 at 14:42 — XTRUST.ORG
– XTRUST.ORG, Commented Sep 5, 2012 at 14:42

user254875486 · Accepted Answer · 2012-09-05 15:07:26Z

7

Because you have 09 (with a preceding 0) this number is interpreted as an octal number, and so it's converted to 0. Use: mktime(23, 50, 0, 9, 5, intval(date("Y")));

You can explore this "feature" a bit;

var_dump(9);   // int 9
var_dump(09);  // int 0
var_dump(07);  // int 7
var_dump(17);  // int 17
var_dump(017); // int 15

EDIT;

date('n'); returns the month without leading zeros. And date('j'); and date('G'); return the day and hour without leading zeros. So you can change mktime(date("H"), date("i"), date("s"), date("m"), date("d"), date("Y")); to mktime(date("G"), date("i"), date("s"), date("n"), date("j"), date("Y"));

There's no way to get the number of minutes and seconds without leading zeros with date() so maybe you need to find another function for that.

EDIT:

To convert 2012.09.05 23:50 to a timestamp you can change the . to / and feed it to strtotime():

$str = '2012.09.05 23:50';
$str = str_replace(".", "/", $str);
$timestamp = strtotime($str);

edited Sep 5, 2012 at 15:07

answered Sep 5, 2012 at 14:41

user254875486

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3 Comments

XTRUST.ORG Over a year ago

So how can I convert 09 to 9?

user254875486 Over a year ago

You have the 09 hardcoded in your code, so you can just change the code. Furthermore; date('n'); returns the month without leading zeros. And date('j'); returns the day without leading zeros

XTRUST.ORG Over a year ago

I can't use a date function as my string format is (2012.09.05 23:50) from .csv file. So I need to convert 09 and 05 to 9 and 5. Do you know how ca I do this? Thanks!

Louis Huppenbauer · Accepted Answer · 2012-09-05 14:43:07Z

0

Leave away the unnecessary zeroes, that should do the trick.

mktime(23, 50, 0, 9, 5, intval(date("Y")));

answered Sep 5, 2012 at 14:43

Louis Huppenbauer

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