Okay, since some people wanted some code to be shown, I created a very simple console application with the help described in the link of Alex. I literally taken that code and placed in the console app.
Some miracle happend, because it worked as soon as I started the app. I don't know what I did wrong in the main application, but it has to be something (duh). Here is the code:
string MyConString = "SERVER=localhost;" +
"DATABASE=database;" +
"UID=root;" +
"PASSWORD=pass;";
System.IO.FileStream fs = new FileStream(@"D:\link\to\image.png", FileMode.Open);
System.IO.BufferedStream bf = new BufferedStream(fs);
byte[] buffer = new byte[bf.Length];
bf.Read(buffer, 0, buffer.Length);
byte[] buffer_new = buffer;
MySqlConnection connection = new MySqlConnection(MyConString);
connection.Open();
MySqlCommand command = new MySqlCommand("", connection);
command.CommandText = "insert into table(fldImage) values(@image);";
command.Parameters.AddWithValue("@image", buffer_new);
command.ExecuteNonQuery();
connection.Close();
Console.WriteLine("Task Performed!");
Console.ReadLine();