Possible Duplicate:
Finding the index of a list in a loop
Assume you have a list, where not just the values have meaning, the index has, too.
counts = [3,4,5,3,1]
Let's say that means "we have 3 objects of type zero, 4 objects of type 1 and so on".
You want to create a list of objects from that and give these objects both information details:
[CountObject(amount=a,type=???) for a in counts]
How would you do that?
Use the enumerate() function:
[CountObject(amount=a, type=i) for i, a in enumerate(counts)]
where i is then the index.
counts and averages for instance), and you also need the index, use zip and itertools.count to avoid nested tuple unpacking: for i, c, a in zip(count(), counts, averages).
Something like:
[CountObject(amount=counts[a],type=a) for a in range(len(counts))]
would do what you want i guess .
beside enumerate() you can also try range(), use xrange() if you're on python 2.x:
[CountObject(amount=counts[i],type=i) for i in range(len(counts))]
