k = [['a'], ['ab'], ['abc']];
alert(k[2].length);
The above code fragment returns 1.
How can I get the length of the string, 3 in this case?
2 Answers
The object is not what is expected. Consider:
k = [['a'], ['ab'], ['abc']];
a = k[2] // -> ['abc']
a.length // -> 1 (length of array)
b = k[2][0] // -> 'abc'
b.length // -> 3 (length of string)
1 Comment
index
Yes. Your array seems a bit off but if you can't control it, @pst's answer is correct. Or you may want to flatten it first so that your code works.
In your example, k is not a normal array containing strings. It contains sub-arrays, which contain the strings. You should declare k this way:
k = ['a', 'ab', 'abc'];
If you do want to use your own declaration, you could do this:
alert(k[2][0].length);
console.log(k[2])and see whatk[2]is?