Passing Customized Parameter in UNIX Shell Scripting

Question

I have parameters named "Country" and "City"

The usual method of running the script is Script.ksh "India" "Mumbai".. ..it will run ok.

But, My requirement is...I want to run this script as Script.ksh -Country "India" -City "Delhi"

Culd any one please get me out of this

Thanks in Advance...

Could you please give one example...using this command? I have no idea on it. — par181
– par181, Commented Aug 3, 2012 at 20:45

evil otto · Accepted Answer · 2012-08-03 23:42:29Z

1

A sample use:

#!/bin/sh

setopt() {
  if [ -n "$1" -a -n "$2" ]; then
    optname=opt_${1#--}
    optval="\"$2\""
    eval $optname="$optval"
    shift
    shift
    setopt "$@"
  fi
}

eval setopt $(getopt -a -l city:,country: -o "" -- "$@")

echo "City is ${opt_city}"
echo "Country is ${opt_country}"

You could use the same technique without getopt, but getopt has the added benefit of normalizing names and recognizing abbreviations (at least GNU getopt does).

$ ./opttest -city "New Delhi" -country India
City is New Delhi
Country is India

$ ./opttest -ci "New Delhi" -co India
City is New Delhi
Country is India

answered Aug 3, 2012 at 23:42

evil otto

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