PHP Class won't return to a String

Question

I'm fairly new to PHP so I have a small problem as I'm learning:

I built a Class called DataStrip.php

<?php

final class DataStrip
{
    public function DataStrip()
    {
        // constructor  
    }

    public function stripVars($vars)
    {

        return $vars;
    }
}
?>

and then I'm trying to pass the public function stripVars a value:

<?php

    include_once ('lib/php/com/DataStrip.php');

    echo($projCat);
    $a = new DataStrip;
    $a->stripVars($projCat);
    echo($a);

?>

however, I get back this error:

( ! ) Catchable fatal error: Object of class DataStrip could not be converted to string in myfilepath

... any advice perhaps on what I could be doing wrong here? Right now this is just a test function as I'm trying to get used to OOP PHP. :)

I assume there is code missing from the given implementation of stripVars()? Can you add it? — beggs
– beggs, Commented Jul 17, 2009 at 2:29

Paolo Bergantino · Accepted Answer · 2009-07-17 02:34:22Z

11

What do you expect it to happen? You're not saving the result of what stripVars returns into a variable:

$result = $a->stripVars($projCat);
print $result;

What you are trying to do is print the object variable itself. If you want to control what happens when you try to print an object, you need to define the __toString method.

edited Jul 17, 2009 at 2:34

answered Jul 17, 2009 at 2:28

Paolo Bergantino

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1 Comment

Tomasz Iniewicz Over a year ago

Paolo, thank you. I did not realize that $a was an object when I was trying to reference it.

Gabriel Sosa · Accepted Answer · 2009-07-17 02:57:06Z

4

if you want to do that... you need declarate the method __toString()

    <?php

    final class DataStrip
    {
    private $vars;

            public function DataStrip()
            {
                    // constructor  
            }

            public function stripVars($vars)
            {

                    $this->vars = $vars;
            }

            public function __toString() {

             return (string) $this->vars;
            }


    }

// then you can do

 $a = new DataStrip;
    $a->stripVars($projCat);
    echo($a);

    ?>

answered Jul 17, 2009 at 2:57

Gabriel Sosa

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Comments

EvilChookie · Accepted Answer · 2009-07-17 02:29:16Z

2

Shouldn't you return to a variable:

$projCat = $a->stripVars($projCat);

When you echo $a you're echoing the object - not any particular function or variable inside it (since when you declare $a you're declaring it as everything in the class - variables, functions, the whole kit and kaboodle.

I also have issues with php oop, so please correct if I am wrong :)

answered Jul 17, 2009 at 2:29

EvilChookie

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