Extracting numbers from a string using regular expressions

Question

I am clueless about regular expressions, but I know that they're the right tool for what I'm trying to do here: I'm trying to extract a numerical value from a string like this one:

approval=not requested^assignment_group=12345678901234567890123456789012^category=Test^contact_type=phone^

Ideally, I'd extract the following from it: 12345678901234567890123456789012 None of the regexes I've tried have worked. How can I get the value I want from this string?

What is the regex you've tried?

gen_Eric
– gen_Eric

2012-07-09 14:44:43 +00:00
Commented Jul 9, 2012 at 14:44 — gen_Eric
– gen_Eric, Commented Jul 9, 2012 at 14:44
Is it the only number you'll ever have?

Madara's Ghost
– Madara's Ghost

2012-07-09 14:44:48 +00:00
Commented Jul 9, 2012 at 14:44 — Madara's Ghost
– Madara's Ghost, Commented Jul 9, 2012 at 14:44

elclanrs · Accepted Answer · 2012-07-09 14:44:44Z

7

This will get all the numbers:

var myValue = /\d+/.exec(myString)

answered Jul 9, 2012 at 14:44

elclanrs

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1 Comment

jaggedsoft Over a year ago

If you want an array of more than one match use myString.match(/\d+/g)

Graham · Accepted Answer · 2012-07-09 14:48:38Z

4

mystr.match(/assignment_group=([^\^]+)/)[1]; //=> "12345678901234567890123456789012"

This will find everything from the end of "assignment_group=" up to the next caret ^ symbol.

answered Jul 9, 2012 at 14:48

Graham

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2 Comments

Olivier Over a year ago

Thanks, I'm using it now. But if there is no number, how do I handle the error? I have: Evaluator.evaluateString() problem

Graham Over a year ago

Do var match = mystr.match(/assignment_group=([^\^]+)/), result = match ? match[1] : ''; to avoid the error and get an empty string instead.

gen_Eric · Accepted Answer · 2012-07-09 15:05:41Z

1

Try something like this:

/\^assignment_group=(\d*)\^/

This will get the number for assignment_group.

var str = 'approval=not requested^assignment_group=12345678901234567890123456789012^category=Test^contact_type=phone^',
    regex = /\^assignment_group=(\d*)\^/,
    matches = str.match(regex),
    id = matches !== null ? matches[1] : '';
console.log(id);

edited Jul 9, 2012 at 15:05

answered Jul 9, 2012 at 14:46

gen_Eric

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Comments

Phillip Schmidt · Accepted Answer · 2012-07-09 15:21:15Z

0

If there is no chance of there being numbers anywhere but when you need them, you could just do:

\d+

the \d matches digits, and the + says "match any number of whatever this follows"

answered Jul 9, 2012 at 15:21

Phillip Schmidt

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2 Comments

Olivier Over a year ago

The regex I've trid was a simple \bassignment_group. I've managed to find another way, by checking the position, and using substring ... it works. But I thought it could have been a nice way to learn regex !

Phillip Schmidt Over a year ago

well if you're trying to learn regex, I'd suggest the tutorial on w3schools.org, though I normally don't recommend that site.

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