I've got a string
Purchases 10384839,Purchases 10293900,Purchases 20101024
Can anyone help me with parsing this? I tried using StringScanner but I'm sort of unfamiliar with regular expressions (not very much practice).
If I could separate it into
myarray[0] = {type => "Purchases", id="10384839"}
myarray[1] = {type => "Purchases", id="10293900"}
myarray[2] = {type => "Purchases", id="20101024"}
That'd be awesome!
string = "Purchases 10384839,Purchases 10293900,Purchases 20101024"
string.scan(/(\w+)\s+(\d+)/).collect { |type, id| { :type => type, :id => id }}
You could do it with a regexp, or just do it in Ruby:
myarray = str.split(",").map { |el|
type, id = el.split(" ")
{:type => type, :id => id }
}
Now you can address it like 'myarray[0][:type]'.
A regular expression wouldn't be necessary, and probably wouldn't be the clearest way to do it. The method you need in this case is split. Something like this would work
raw_string = "Purchases 10384839,Purchases 10293900,Purchases 20101024"
myarray = raw_string.split(',').collect do |item|
type, id = item.split(' ', 2)
{ :type => type, :id => id }
end
Documentation for the split and collect methods can be found here:
Here is an irb session:
dru$ irb
irb(main):001:0> x = "Purchases 10384839,Purchases 10293900,Purchases 20101024"
=> "Purchases 10384839,Purchases 10293900,Purchases 20101024"
irb(main):002:0> items = x.split ','
=> ["Purchases 10384839", "Purchases 10293900", "Purchases 20101024"]
irb(main):006:0> items.map { |item| parts = item.split ' '; { :type => parts[0], :id => parts[1] } }
=> [{:type=>"Purchases", :id=>"10384839"}, {:type=>"Purchases", :id=>"10293900"}, {:type=>"Purchases", :id=>"20101024"}]
irb(main):007:0>
Essentially, I would just split on the ',' first. Then I would split each item by space and create the hash object with the parts. No regex required.
s = 'Purchases 10384839,Purchases 10293900,Purchases 20101024'
myarray = s.split(',').map{|item|
item = item.split(' ')
{:type => item[0], :id => item[1]}
}
map and collect?