Python timeit and program output

Question

Is there any way to use the timeit function to output both the function result and the time it took to process at the same time?

Right now I am using

timer = Timer('func()', 'from __main__ import func')
print timer.timeit(1)

But this just outputs the time and not the program output, which returns something at its end. I want it to output

FuncOutputGoesHere 13.2897528935

on the same line.

Ideally, I'd like to be able to take an average of the program by running it N times and then outputting the program result and its average time (a total of one output overall)

I seem to see a lot of deviation between people recommending timeit and people recommending time.time(). Which is better? — MyNameIsKhan
– MyNameIsKhan, Commented Jun 4, 2012 at 16:44
timeit uses time.time(), unless you are on windows, where it'll use time.clock (more accurate). — Martijn Pieters
– Martijn Pieters, Commented Jun 4, 2012 at 16:46
My answer gives you the same code as what timeit uses. It'll be just as accurate. — Martijn Pieters
– Martijn Pieters, Commented Jun 4, 2012 at 16:47
Updated my answer; if you are running it more than once anyway, why not run it once more to capture the return value? — Martijn Pieters
– Martijn Pieters, Commented Jun 4, 2012 at 16:54

Martijn Pieters · Accepted Answer · 2012-06-04 16:54:00Z

19

Two options:

Include 'print' in your timed code. Ugly, but hey.

timer = Timer('print func()', 'from __main__ import func')
print timer.timeit(1)

If all you do is run your function once, then dispense with the timeit module altogether and time the code directly using the same method:

import sys
import time

if sys.platform == "win32":
    # On Windows, the best timer is time.clock()
    default_timer = time.clock
else:
    # On most other platforms the best timer is time.time()
    default_timer = time.time

t0 = default_timer()
output = func()
t1 = default_timer()
print output, t1 - t0

If you want to run the code multiple times, and produce the output, why not run the code once outside the timeit function? You are calling it more than once then already anyway:

    timer = Timer('func()', 'from __main__ import func')
    print timer.timeit(100),
    print func()

edited Jun 4, 2012 at 16:54

answered Jun 4, 2012 at 16:42

Martijn Pieters

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Comments

Bakuriu · Accepted Answer · 2012-06-04 16:43:20Z

0

The timeit module executes the statement passed. You could just print the result of the function:

timer = Timer('print func()', 'from __main__ import func')
print timer.timeit(1)

answered Jun 4, 2012 at 16:43

Bakuriu

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4 Comments

user395760 Over a year ago

This would print it a million times, or however often the statement is executed, and also count the I/O overhead into the timings.

Martijn Pieters Over a year ago

@delnan: he runs timer.timeit(1)... Make of that what you will. :-P

MyNameIsKhan Over a year ago

@MartijnPieters I don't know how to run it multiple times without it outputting multiple times; also I think I'd need to divide the result by the number of runtimes because it seems to be aggregate. It'd be ideal to run it a few times to get an average and output once.

Martijn Pieters Over a year ago

Yes, it aggregates total runtime. See the timeit documentation.

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