How to introduce JavaScript alert window inside PHP code

Question

I need to introduce JavaScript alert function show_alert() inside PHP code. How this can be done?

script type="text/javascript">
        function show_alert() {
            var msg = "No solution found.";
            alert(msg);
        }
</script>
<?php
//...
    $outputs = -1;
    if ($outputs == -1) {
        echo '<script type="text/javascript"> show_alert(); </script>';
    } else {
        ?>
        <table width="100%">
            <tr>
                <td width="100%"> 
                    <div class="scrollbar" id="chart">
                        <img src="ganttchart.php">
                    </div>
                </td>
            </tr>
        </table>
    <?php
    }
?>

alexpja · Accepted Answer · 2012-05-19 22:48:50Z

6

Try this, it echos the show_alert(); in PHP:

<script type="text/javascript">
    function show_alert() {
    var msg = "No solution found";
    alert(msg);
    }
</script>

<?php
//...

$output = run_function();
if ($output == -1) {
   echo '<script type="text/javascript"> show_alert(); </script>';
}
?>

edited May 19, 2012 at 22:48

answered May 19, 2012 at 22:43

alexpja

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18 Comments

Klausos Klausos Over a year ago

I tried this code. Alert window doesn't pop-up. I tried to debug this code, but the cursor jumps over show_alert() line...

alexpja Over a year ago

Try now, fixed $outputs to $output

alexpja Over a year ago

Tested it locally with $output = -1; instead of $output = run_function();, works for me.

Klausos Klausos Over a year ago

Well, if you say it works for you, I will accept the answer. For some strange reason I don't see alert box.

alexpja Over a year ago

$output = run_function(); if ($outputs == -1) { See what I mean? This is from your post. Either $output should be $outputs or viceversa.

|

Ignacio Vazquez-Abrams · Accepted Answer · 2012-05-19 22:38:35Z

6

In-line JavaScript needs to be inside <script> tags. Simply output those as well, in a valid place. Do note that you cannot affect the operation of the PHP code this way though.

answered May 19, 2012 at 22:38

Ignacio Vazquez-Abrams

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2 Comments

Klausos Klausos Over a year ago

Could you give an example? I tried your suggestion,but probably I did something wrong.

David Over a year ago

@KlausosKlausos: In what way doesn't it work? Update the question to show the client-side code actually being rendered in the browser. (Hint: If the indented code block isn't in the page source then $outputs doesn't equal -1. Which means the code does work and does exactly what it's intended to do.)

aurel · Accepted Answer · 2012-05-19 22:41:41Z

1

use this

<script type="text/javascript">
         show_alert();
    </script>

so like this

$output = run_function();
if ($outputs == -1) {
?>
<script type="text/javascript">
             show_alert();
        </script>
<?php
}
?>

answered May 19, 2012 at 22:41

aurel

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3 Comments

Klausos Klausos Over a year ago

I don't know why, but it doesn't work. Alert window should pop-up, but it doesn't. I tried to debug this code. Indeed the cursor jumps over show_alert() line...

aurel Over a year ago

does the if statement work? if u echo some php would it work? it might be that $output never == -1. But not sure - sorry

Klausos Klausos Over a year ago

No,output is equal to -1. That's the case.

comu · Accepted Answer · 2012-05-19 22:55:07Z

0

<?php
    $output = run_function();
    if ($outputs == -1) {
        echo "<script type='text/javascript'>alert("No Solution Found");</script>"
    }
?>

answered May 19, 2012 at 22:55

comu

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3 Comments

alexpja Over a year ago

My answer is almost the same :/

comu Over a year ago

Mine doesn't ask for a global function that was already defined in the Javascript. Instead, it just runs it without looking for a function

alexpja Over a year ago

True, but he had the global function in his so I included that in mine.

Johntor · Accepted Answer · 2012-05-19 23:01:52Z

0

I would suggest

    $msg = "My message";
    echo "<script type=\"text/javascript\"> alert($msg); </script>";

You are right about it David

edited May 19, 2012 at 23:01

answered May 19, 2012 at 22:52

Johntor

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3 Comments

David Over a year ago

Your double-quotes are probably doing to confuse the parser and produce an error.

alexpja Over a year ago

or just use 'text/javasript' instead since you are using the double quotes for the echo?

Johntor Over a year ago

I think that double quotes (") are more xhtml like and I prefer them!

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