fetching form value in an array in jQuery

Question

i have this dynamically populated form fields.

<input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>

on jQuery's keyup i want to fetch all the value from input[name="quantity[]"] and perform some calculations like total quantity i.e something like

(field1 quantity value) + (field2 quantity value) + (field3 quantity value) ... n

i tried fetching the value like this.

$('input[name="quantity[]"]').keyup(function(){
    var val = $(this).val();
});

this only fetches the value of first element and ignores the rest of fields. how do i go with what i want?

thank you

Iori Yagami · Accepted Answer · 2012-05-04 05:47:54Z

2

try this:

 <input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>
<input type="text" name="quantity[]" placeholder="quantity"/>

<input type="text" name="res" placeholder="Resultado"/>



$(document).ready(function() {


$('input[name="quantity[]"]').keyup(function(){
   var val = 0;
   $('input[name="quantity[]"]').each(function() {
                val += Number($(this).val());
            });
    $('input[name="res"]').val(val);
});

});

fuente con jsfiddle

http://jsfiddle.net/kSw4G/3/

by JNE

answered May 4, 2012 at 5:47

Iori Yagami

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Comments

Jack · Accepted Answer · 2012-05-04 05:36:32Z

2

var $quantity = $('input[name="quantity[]"]');

$quantity.keyup(function(){
    var val = 0;
    $quantity.each(function(){
        val += parseInt($(this).val(), 10);
    });
});

answered May 4, 2012 at 5:36

Jack

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3 Comments

Ibrahim Azhar Armar Over a year ago

just out of curiosity, what is the use of second argument in parseInt()?

Jack Over a year ago

Just to insure that you are adding numeric values rather than concatenating strings. The + operator does double duty in JavaScript, and .val() returns a string. It is necessary to convert this to a numeric value if you want to math operations.

Ibrahim Azhar Armar Over a year ago

does not work for the second field, this only fetches the value from first field

thecodeparadox · Accepted Answer · 2012-05-04 05:57:26Z

1

var ref = $('input[name^="quantity"]');
    ref.keyup(function(e){
        var result = 0;
        ref.each(function() {
          console.log($(this).val());
          if($(this).val().length && $(this).val() != '') {
            result += parseInt($(this).val());
          }
          console.log(result);
        });
    });

Live Demo

edited May 4, 2012 at 5:57

answered May 4, 2012 at 5:35

thecodeparadox

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7 Comments

Ibrahim Azhar Armar Over a year ago

since the value is being fetched as string i am getting an error NaN, how do i force jQuery to treat it as integer?

Ibrahim Azhar Armar Over a year ago

noticed that parstInt already does that. then how come i am getting NAN error

Muhammad Raheel Over a year ago

you can do it like this if(val == ""){result += 0}else{result += parseInt(val);}

Ibrahim Azhar Armar Over a year ago

this have some logical error. if i change the field value then it will keep appending from the last value it fetched. for example if i have value of 100 in field 1 and then if i change it to 200 it will result in 300

Ibrahim Azhar Armar Over a year ago

still the calculation does not come proper

|

thecodeparadox · Accepted Answer · 2012-05-04 05:40:25Z

0

A simple solution is to assign each text box a class let suppose quantity then

var total_quantity = 0;  
$('.quantity').keyup(function()
{
    $(this).each(function()
    {
        total_quantity += $(this).val();
    });
});

edited May 4, 2012 at 5:40

thecodeparadox

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answered May 4, 2012 at 5:38

Muhammad Raheel

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