Why am I getting error message "Cannot use object of type stdClass as array"?

Question

I have a object $images that looks like this:

stdClass Object
(
    [0] => stdClass Object
        (
            [id] => 125
            [title] => 131301
            [file_name] => 131301
            [file_ext] => jpg
            [dir] => Adventure/
            [fk_gallery_id] => 1
        )

    [1] => stdClass Object
        (
            [id] => 126
            [title] => 181301
            [file_name] => 181301
            [file_ext] => jpg
            [dir] => Adventure/
            [fk_gallery_id] => 1
        )
);

Now I want to get the first element in the object:

$obj = $images[0].

This gives me the error:

Fatal error: Cannot use object of type stdClass as array

Can anyone tell me why this is not working?

I've also tried $images[0]->id, but this is not working either.

Because you have an object and not an array... like the error message says. — Felix Kling
– Felix Kling, Commented Apr 16, 2012 at 12:40

user142162 · Accepted Answer · 2012-04-16 12:40:21Z

3

They are class members, therefore you need to access them like this:

$obj = $images->{0};

See: Variable variables.

answered Apr 16, 2012 at 12:40

user142162

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1 Comment

Steven Over a year ago

Aha.Thanks, I didn't know that. This removes the error. But doing a print_r($obj)shows nothing. And echo $obj->title also shows nothing.

Joyce Babu · Accepted Answer · 2012-04-16 13:15:29Z

1

$images is not an array, it is an object of the type StdClass (standard class is actually a dummy class). To access class members, you have to use the format

$object->membername

Unfortunately, 0 is not a valid member name. Hence you cannot use $images->0. The workaround is to use the format

$images->{"0"}

The following will also work (Depending on your PHP version)

$a = 0;
$images->$a;

edited Apr 16, 2012 at 13:15

answered Apr 16, 2012 at 12:46

Joyce Babu

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5 Comments

Steven Over a year ago

Yes, $tim-cooper already explained this. But it's not working for me. See my comment.

Joyce Babu Over a year ago

my bad. you need to use $images->{"0"}

Steven Over a year ago

Thanks, that worked like a charm. - Actually, I was a bit too quick. The result is the same - I get nothing.

Joyce Babu Over a year ago

Try this code. Is it working? $tmp = json_decode('{"0": [1, 2, 3]}'); print_r($tmp->{"0"});

Joyce Babu Over a year ago

If that works, then the problem is not with the code. Check $images and ensure that id is not empty. Are you getting any notices? try setting error_reporting(E_ALL | E_NOTICE);

scibuff · Accepted Answer · 2012-04-16 12:40:16Z

0

try

$obj = $images["0"];

or

$key = 0;
$obj = $images[ $key ];

answered Apr 16, 2012 at 12:40

scibuff

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Comments

Vipin Jain · Accepted Answer · 2012-04-16 12:54:22Z

0

Use this as the images is also an object and inside one are also objects

$images->{0}->id;

edited Apr 16, 2012 at 12:54

answered Apr 16, 2012 at 12:43

Vipin Jain

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Comments

Wouter Dorgelo · Accepted Answer · 2012-07-16 13:36:59Z

0

Try this:

$a = $image->0;
$id = $a->id

edited Jul 16, 2012 at 13:36

Wouter Dorgelo

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answered Apr 16, 2012 at 12:42

Mohit Bumb

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Comments

user252566 · Accepted Answer · 2014-04-19 12:43:12Z

0

Try $image->0->id This might work for your code

answered Apr 19, 2014 at 12:43

user252566

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