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Physics F3 (IGCSE) speed, velocity and acceleration
This document covers key concepts in physics related to speed, velocity, acceleration, and motion graphs. It defines speed and velocity, distinguishing that velocity includes direction while speed does not. It describes how to calculate average speed, acceleration, and uses graphs of distance-time and velocity-time to analyze motion. Constant acceleration is examined through examples of calculating final velocity. The document also discusses free fall near Earth and how objects accelerate at approximately 9.8 m/s2 due to gravity.
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Physics F3 (IGCSE) speed, velocity and acceleration
- 1. PHYSICS – Speed,velocity and acceleration
- 2. LEARNING OBJECTIVES 1.2 Motion Core • Definespeed and calculate average speed from total time / total distance • Plot and interpret a speed-time graph or a distance- time graph • Recognise from the shape of a speed- time graph when a body is – at rest – moving with constant speed – moving with changing speed • Calculate the area under a speed-time graph to work out the distance travelled for motion with constant acceleration • Demonstrate understanding that acceleration and deceleration are related to changing speed including qualitative analysis of the gradient of a speed-time graph • State that the acceleration of free fall for a body near to the Earth is constant Supplement • Distinguish between speed and velocity • Define and calculate acceleration using time taken change of velocity • Calculate speed from the gradient of a distance-time graph • Calculate acceleration from the gradient of a speed-time graph • Recognise linear motion for which the acceleration is constant • Recognise motion for which the acceleration is not constant • Understand deceleration as a negative acceleration • Describe qualitatively the motion of bodies falling in a uniform gravitational field with and without air resistance (including reference to terminal velocity)
- 3. A Average speed+= Distancemoved Time taken
- 4. A Average speed+= Distancemoved Time taken Distance measured in metres (m) Time measured in seconds (s) Speed - metres per second (m/s)
- 5. A Average speed+= Distancemoved Time taken Example: Car travels 50m time 2s speed = 50/2 = 25 m/s 25 m.s-1
- 6. So if that’s speed,what is velocity?
- 7. Velocity is speedin a given direction.
- 8. Velocity is speedin a given direction. Velocity is 25m/s due west
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- 12. Example: Cyclist +10m/s tothe right
- 13. Example: Cyclist +10m/s tothe right -10m/s to the left
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- 15. What’s your vector Victor? Quantitiessuch as velocity are called vectors because they have size and direction
- 16. Acceleration is therate at which an object increases speed or velocity.
- 17. Acceleration is therate at which an object increases speed or velocity. Acceleration = change in velocity time taken
- 18. Acceleration is therate at which an object increases speed or velocity. Acceleration = change in velocity time taken Also written as: a = v - u t
- 19. Acceleration is therate at which an object increases speed or velocity. Acceleration = change in velocity time taken Velocity measured in m/s Time measured in s Acceleration measured in m/s/s or m/s2
- 20. Example: a dragcar increases its velocity from zero to 60m/s in 3s. a = v - u t
- 21. Example: a dragcar increases its velocity from zero to 60m/s in 3s. a = v - u t a = 60 – 0 3
- 22. Example: a dragcar increases its velocity from zero to 60m/s in 3s. a = v - u t a = 60 – 0 3 a = 60 = 20m/s-2 3
- 23. Example: a dragcar increases its velocity from zero to 60m/s in 3s. a = v - u t a = 60 – 0 3 a = 60 = 20m/s-2 3 Don’t forget that acceleration is a vector – it has size and direction
- 24. Deceleration (retardation) Deceleration is negative acceleration– the object is slowing down. Eg. – 4m/s2
- 25. Constant acceleration example AB 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B?
- 26. Constant acceleration example AB 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B? Solution: car gains 4m/s of velocity every second. In 6s it gains an extra 24m/s.
- 27. Constant acceleration example AB 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B? Solution: car gains 4m/s of velocity every second. In 6s it gains an extra 24m/s. Final velocity = initial velocity + extra velocity
- 28. Constant acceleration example AB 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B? Solution: car gains 4m/s of velocity every second. In 6s it gains an extra 24m/s. Final velocity = initial velocity + extra velocity Final velocity = 10 + 24 = 34m/s
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- 32. Travelling at constantspeed Stationary
- 33. Travelling at constantspeed Stationary Travelling at constant speed
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- 35.
- 36.
- 37. Speed = distance time Speed= 8 = 1 km/h 8
- 38. Acceleration from velocity: time graph
- 39. Acceleration from velocity: time graph Steady acceleration
- 40. Acceleration from velocity: time graph Steady acceleration Steady velocity
- 41. Acceleration from velocity: time graph Steady acceleration Steady velocity Steady deceleration
- 42. Acceleration from velocity: time graph Acceleration = V - U t
- 43. Acceleration from velocity: time graph Acceleration = V - U t
- 44. Acceleration from velocity: time graph Acceleration = 3 – 0 / 2 = 1.5 m/s/s (m.s-2)
- 45. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph.
- 46. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = V - U t
- 47. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 40 - 0 = 4m/s2 10
- 48. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 0 (no change in velocity)
- 49. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 20 - 0 = 2m/s2 10
- 50. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 0 - 60 = -3m/s2 20
- 51. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled.
- 52. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height.
- 53. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2
- 54. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2
- 55. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2
- 56. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2 Area = 100m2
- 57. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2 Area = 100m2 Area = 600m2
- 58. Velocity-time graphs 80 60 40 20 0 10 2030 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2 Area = 100m2 Area = 600m2 The total distance travelled = 200 + 400 + 400 + 100 + 600 = 1700m
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- 60. Acceleration of freefall (g) Which object will hit the ground first?
- 61. Acceleration of freefall (g) Which object will hit the ground first? Obviously the brick (because the feather is slowed much more by the air)
- 62. Acceleration of freefall (g) No air resistance, objects both fall with the same downward acceleration. In air In a vacuum
- 63. Acceleration of freefall (g) No air resistance, objects both fall with the same downward acceleration. In air In a vacuum Acceleration of free fall = 9.8m/s2 Given the symbol ‘g’
- 64. Acceleration of freefall (g) No air resistance, objects both fall with the same downward acceleration. In air In a vacuum Acceleration of free fall = 9.8m/s2 Given the symbol ‘g’
- 65.
- 66. Acceleration and gravity Fallingobjects accelerate towards the ground at 10m/s2 due to gravity. The force of gravity always acts towards the centre of the Earth. The atmosphere creates an upward force that slows down falling objects. This is known as air resistance or drag.
- 67. Acceleration and gravity Fallingobjects accelerate towards the ground at 10m/s2 due to gravity. The force of gravity always acts towards the centre of the Earth. The atmosphere creates an upward force that slows down falling objects. This is known as air resistance or drag.
- 68. Acceleration and gravity Fallingobjects accelerate towards the ground at 10m/s2 due to gravity. The force of gravity always acts towards the centre of the Earth. The atmosphere creates an upward force that slows down falling objects. This is known as air resistance or drag. The larger the surface area of the object, the larger the drag force
- 69. Acceleration and gravity Speed(m/s) Time(s) Drag Weight A At first the force of gravity is larger than the drag force, so the object accelerates.
- 70. Acceleration and gravity Speed(m/s) Time(s) Drag Weight B As speed increases, so does drag; the acceleration decreases
- 71. Acceleration and gravity Speed(m/s) Time(s) Drag Weight C When drag equals the force due to gravity there is no resultant force and the acceleration is zero. The object continues at terminal velocity. Terminal velocity
- 72. LEARNING OBJECTIVES 1.2 Motion Core • Definespeed and calculate average speed from total time / total distance • Plot and interpret a speed-time graph or a distance- time graph • Recognise from the shape of a speed- time graph when a body is – at rest – moving with constant speed – moving with changing speed • Calculate the area under a speed-time graph to work out the distance travelled for motion with constant acceleration • Demonstrate understanding that acceleration and deceleration are related to changing speed including qualitative analysis of the gradient of a speed-time graph • State that the acceleration of free fall for a body near to the Earth is constant Supplement • Distinguish between speed and velocity • Define and calculate acceleration using time taken change of velocity • Calculate speed from the gradient of a distance-time graph • Calculate acceleration from the gradient of a speed-time graph • Recognise linear motion for which the acceleration is constant • Recognise motion for which the acceleration is not constant • Understand deceleration as a negative acceleration • Describe qualitatively the motion of bodies falling in a uniform gravitational field with and without air resistance (including reference to terminal velocity)
- 73. PHYSICS – Speed,velocity and acceleration