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Fix：示例代码错误 #1239

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Fix：示例代码错误 #1239

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2 changes: 1 addition & 1 deletion 1-js/06-advanced-functions/09-call-apply-decorators/article.md
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Expand Up @@ -319,7 +319,7 @@ func.apply(context, args);
这是它的最简形式：

```js
let wrapper = function() {
let wrapper = function(func) {
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@songhn233 songhn233 Jan 4, 2025 •
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这里如果加入参的话需要增加一个闭包

原文里意图是把 wrapper 当作 func 一样使用，所以 apply 这里有个 arguments 的透传。即 fn(xxx) 等同于 wrapper(xxxx)，这么改 arguments 读了 func 又作为参数传给了自己就不对了

传 func 的话就应该是

let fn = function(func) {
  function wrapper() {
     return func.apply(this, arguments);
  }
  return wrapper;
};

之后通过 fn(x) 得到 x 的 wrapper

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@songhn233 songhn233 Jan 4, 2025

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这个例子主要还是想用 wrapper 的 apply 来说明执行和 func 一样，所以 wrapper 的 arguments 直接透传给了 fn

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@Allen-su Allen-su Jan 5, 2025

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这个例子主要还是想用 wrapper 的 apply 来说明执行和 func 一样，所以 wrapper 的 arguments 直接透传给了 fn

确实是这样，我理解错了，这里本意是一个用于返回的包装器

return func.apply(this, arguments);
};
```
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