pass arguments from script to script

Assuming that the parameter expansions in test2.sh are correctly quoted as

find "$1" -type f -mmin +"$2" -exec rm -f {} \;

then test3.sh might have a call to test2.sh like this:

test2.sh "some file name" 5

$1 in test2.sh will expand to the string some file name and $2 will expand to 5.

This is assuming that test2.sh is located in a directory that is listed in the PATH variable of test3.sh. If not, use a full path (absolute or relative), for example:

./test2.sh "some file name" 5

It also assumes that test2.sh has first been made executable with chmod +x test2.sh and that it has a correct #!-line.

After clarification in comment below:

The test3.sh script could do (assuming it's a bash script):

read -p 'Enter directory name: ' dirname
read -p 'Enter number of days: ' days

minutes=$(( days * 60 * 24 ))

./test2.sh "$dirname" "$minutes"

The next step would be to validate the user's input so that $days is an actual integer and so that $dirname is a valid name of a directory.

If it's not bash but sh:

printf 'Enter directory name: '
read -r dirname

(etc.)

Most implementations of find also have -delete:

find "$1" -type f -mmin +"$2" -delete