I have file called log.txt. file contains are like below :-
/proc
used avail
10 100
how can i extract the below strings from that file using shell script. I want the below strings to be extracted.
/proc
10
100
4 Answers
awk '{print $1 $4 $5}' log.txt
2 Comments
user358232
thx, but actually the file content is not like above. its like :- In the first line its only /proc. in the second line its "used" and "avail" and in the next line "10" and "100". below "used" its "10" and below "avail" its "100". the structure is like this. hope u can uderstand what i want to describe here
user358232
please have a look at my question in 1st page(scroll up)... ur answer is not working for that
awk '/\/proc/ {print;getline;getline;print $1"\n"$2}' log.txt
The above awk command calls getline twice whenever a line matches /proc. The print statement then prints out the second line after the match.
Output:
/proc
10
100
Comments
Using sed, and if it is spaces you have between 10 and 100:
sed -e '2d;3s/ */\n/' log.txt
if it is tabs you have between 10 and 100, and you gave GNU sed:
sed -e '2d;3s/\t\t*/\n/' log.txt
if it is tabs you have between 10 and 100, and you do not have gave GNU sed, but real tabs instead of the 2 \t above.
Comments
Avoiding sed (or awk) and using standard UNIX utilities, and if it is spaces you have between 10 and 100:
paste -s -d " " file | tr -s " " | cut -d " " -f 1,4,5 | tr " " "\n"
if it is tabs you have between 10 and 100, and you have GNU utilities:
paste -s -d "\t" file | tr -s "\t" | cut -f 1,4,5 | tr "\t" "\n"
if it is tabs you have between 10 and 100, and you do not have gave GNU utilities, but real tabs instead of the \t above and a real instead of the \n.
log.txtas well as your actual expected output rather than expecting the StackOverflow community to guess. Thanks ever-so!