I have been learning about shell scripting and regular expressions. I want to find a way to extract a specific part from the file name below.
profiles_060315091024_30398-r-00006.avro
I want to extract the number 30398 from the file name.
Thanks
using awk:
str='profiles_060315091024_30398-r-00006.avro'
awk -F'[_-]' '{print $3}' <<< "$str"
30398
-F'[_-]' is setting a custom field separator as _ or -
myvar=$(awk -F'[_-]' '{print $3}' <<< "$str")print $3 is required so that awk can print 3rd field in the given input.
awk as IFS='_-' read x x myvar x <<< "${str}"...Using shell only. I assume you want the digits between the underscore and the hyphen.
regular expression (bash specific)
filename=profiles_060315091024_30398-r-00006.avro
if [[ $filename =~ _([0-9]+)- ]]; then num=${BASH_REMATCH[1]}; fi
echo $num
# => 30398
using parameter expansion (any POSIX shell)
tmp=${filename##*_} # remove from the start up to last underscore
tmp=${tmp%%-*} # remove the first hyphen until end of string
echo $tmp
# => 30398
