how to iteratively create variables to use in a function

Question

I have multiple variables that were created, stringa - stringc. I am trying to find a way to iterative create these variable names and use them as input for a function, without having to type them in individually.

import string

stringa = ['item1', 'item2', item3']
stringb = ['sitem1', 'sitem2']
stringc = ['sitemc', 'sitemc']
    
def edittext(t):
    t = t.upper()
    return t

finallist = []
for i in range(3):
    letter = string.ascii_lowercase[i]
    finalist.append('string' + letter)
    finallist.append(edittext(('string' + letter).strip('\'')))

This is my output for the finallist.

Out [212]: ['stringa', 'STRINGA', 'stringb', 'STRINGB', 'stringc', 'STRINGC']

This is what I'm trying to accomplish:

['stringa', 'item1', 'item2', item3', 'stringb', 'sitem1', 'sitem2', 'stringc', 'sitemc', 'sitemc']

I thought about using dictionaries, but I don't think it would work. This is a simplified version of my problem. For the real problem, each of my variables contains a list of items. — Lee
– Lee, Commented Jul 10, 2020 at 5:18

MrNobody33 · Accepted Answer · 2020-07-10 06:02:00Z

2

You can try with join and after mapping with list.map the string with your custom function:

import string

doc = ['This is the first string', 'This is the second string' ,'This is the third string']

def edittext(t):
    t = t.upper()
    return t

edited_doc=[]
for i,val in enumerate(doc):
    edited_doc.append('string'+string.ascii_lowercase[i])
    edited_doc.append(' '.join(map(edittext,val.split())))
    
print(edited_doc)

Output:

['stringa', 'THIS IS THE FIRST STRING', 'stringb', 'THIS IS THE SECOND STRING', 'stringc', 'THIS IS THE THIRD STRING']

Also as a suggestion, and as @Muhammadrasul said, you are assigning pairs of (key,value), so you can consider using a dictionary:

import string

doc = ['This is the first string', 'This is the second string' ,'This is the third string']

def edittext(t):
    t = t.upper()
    return t

edited_dict={'string'+string.ascii_lowercase[i]:' '.join(map(edittext,val.split())) for i,val in enumerate(doc)}

print(edited_dict)

Output:

{'stringa': 'THIS IS THE FIRST STRING', 'stringb': 'THIS IS THE SECOND STRING', 'stringc': 'THIS IS THE THIRD STRING'}

edited Jul 10, 2020 at 6:02

answered Jul 10, 2020 at 5:15

MrNobody33

6,5039 silver badges20 bronze badges

Sign up to request clarification or add additional context in comments.

9 Comments

Pynchia Over a year ago

Why use indexes? Python is a master of iteration without them. Please edit and iterate better on doc

MrNobody33 Over a year ago

I know that, I used indexes to the string.ascii_lowercase[i] assignation @Pynchia.

MrNobody33 Over a year ago

Yes, that can be an option too. I didn't think about it. I will change it to enumerate based on this posts https://stackoverflow.com/questions/4852944/what-is-faster-for-loop-using-enumerate-or-for-loop-using-xrange-in-python and https://stackoverflow.com/questions/522563/accessing-the-index-in-for-loops.

MrNobody33 Over a year ago

I will changed it to enumerate, don't worry. And I know the OP can just use upper, but maybe the function could be other, as you can see @Pynchia. Also, why don't you say from the beginning that I should use enumerate and why I should use it, instead of downvote the answer(I guess) and pointing as an "awful solution". That shouldn't be the attitude for this Q/A site. We are all learning here.

MrNobody33 Over a year ago

You're welcome @Lee, I'll edit the answer using enumerate. If you find it helpful, consider accepting it ! :)

|

Collectives™ on Stack Overflow

how to iteratively create variables to use in a function

1 Answer 1

9 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

9 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related