python regex extract string between characters [duplicate]

Question

I have a string:

x = "abc/xyz/foo/bar/foobar.mp3"

How to extract foobar out of it?

I have done it in this way:

import re
re.search(r'\/[a-z]+.mp3', x)

Although, I do not know how to extract the matched string without '.' and without '.mp3'.

I do not want to do Python splits, rplist, partition etc. as it adds extra functions. I want it to be as simple and short as possible.

EDIT:

(it's a duplicate assume it's a file path. Given the .mp3 I'd think that it is) — user202729
– user202729, Commented May 28, 2019 at 8:06

CertainPerformance · Accepted Answer · 2019-05-28 08:06:49Z

1

Match non-slashes, then lookahead for \.mp3$:

re.search(r'[^/]+(?=\.mp3$)', x)

Make sure to escape the . with a backslash, else it will match any character.

answered May 28, 2019 at 8:06

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Comments

Code Maniac · Accepted Answer · 2019-05-28 08:07:03Z

1

You can use this

[a-z]+(?=\.mp3$)

[a-z]+ - matches alphabets one or more time
(?=\.mp3$) - positive lookahead to check match must be followed by .mp3 and end of line

answered May 28, 2019 at 8:07

Code Maniac

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