Uploading binary file to API using python

Question

I am trying to upload a package binary over to the RestAPI of storage using python. But it keeps throwing error and couldn't upload the file. Below is the code I am using to achieve it :

jsonheaderup={'Content-Type': 'application/octet-stream'}

file = open('install.pkg.gz', 'rb')
files = {'file': file}

def upload_code():

  u = requests.post("%s/api/sys/v2/updates" % (url), files=files, verify=False,      headers=jsonheaderup)
  l = json.loads(u.text)

upload_code()

I tried to change the jsonheader file type to application/x-gzip . But now it gives an argument error, even though everything is present : Error : {u'fault': {u'message': u'required input argument is missing (upload)', u'code': 400, u'name': u'ERR_MISSING_ARG'}} — Sarang Sangram
– Sarang Sangram, Commented Sep 12, 2018 at 10:38
And BTW, if you have more info, like your first comment, you can edit your original post to include it. — rickhg12hs
– rickhg12hs, Commented Sep 13, 2018 at 7:50

Ninita · Accepted Answer · 2020-02-27 20:49:45Z

3

The earlier posts didn't really helped but I figured it out by referring the original doc of requests: Streaming uploads. Check doc here.

As my file was huge around 1.9 GB, so session was breaking in between the upload process, hence giving error as "Internal error".

As its huge file I streamed and upload it by providing a file-like object in my function:

def upload_code():
  jsonheaderup={'Content-Type': 'application/octet-stream'}
  with open('/root/ak-nas-2013-06-05-7-18-1-1-3-nd.pkg.gz', 'rb') as file:
    requests.post("%s/api/system/v1/updates" % (url), data=file, auth=zfsauth, verify=False, headers=jsonheaderup, timeout=None)

edited Feb 27, 2020 at 20:49

Ninita

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answered Sep 14, 2018 at 6:22

Sarang Sangram

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Comments

carapaece · Accepted Answer · 2018-09-12 09:12:17Z

0

At first glance, I can not see any mistake.

Did you see this: Python 3 script to upload a file to a REST URL (multipart request) ?

answered Sep 12, 2018 at 9:12

carapaece

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