I get an issue using REGEX, it is probably about my REGEX but I need some helps.
I need to match all string containing "D"...
Test string 1 : D
Test string 2 : aaaaaaDqqqqq
Test string 3 : Dssssssss
Test string 4 : D4564646
Test string 5 : 1321313D2312
Test string 6 : ppppprrrrrr
My regex :
/^.+D.+|(:?^|\s)D$/gi
It works only for 1 and 2 and it should works for 1, 2, 3, 4 and 5.
In your case problem is with + operator which is literally Matches between one and unlimited times so it wont work if letter "D" will be in the beggining or the end of string. Try this regex: ^.*D.*$ with asterix, as it is defined as Matches between zero and unlimited times
^.*D.*$ is inefficient and will choke on multiline input. Do not use it.Following regex should work for you
.*D.*
.*D.* is inefficient and will choke on multiline input. Do not use it.If all you need to do is test for whether or not a string contains a D character, it's just /D/
var tests = [
"D",
"aaaaaaDqqqqq",
"Dssssssss",
"D4564646",
"1321313D2312",
"ppppprrrrrr"
]
tests.forEach(str => console.log(/D/.test(str)))Instead of using a regex simply use the includes function
var string = "aaaaaaDqqqqq",
substring = "D";
if(string.includes(substring)){
console.log("contain")
}else{
console.log("don't contain")
}
^.*D.*$? Or[^D]*D[\s\S]*..*.indexOforincludes, which is a more natural way to check if a char exists in an input string in JavaScript.