Bash Script SSH Commands on Remote Server Not Executing as Expected [duplicate]

Question

So I've got a bash script in which I want to SSH onto one of my remote servers and run some commands. This is my code:

MYFUNCTION="
function my_function
{
    VAR=$(readlink -f current | sed 's/[^)
}
my_function
"

ssh -l ${USERNAME} ${HOSTNAME} "${MYFUNCTION}"

The problem is that the VAR variable is not being populated with the command output as it should. I've run the exact same command myself, and I get the desired output, but when doing it through SSH in the bash script, it doesn't work as expected. What am I doing wrong here?

my_function() { is POSIX-compliant syntax -- the way you're declaring your function is legacy ksh syntax supported by bash only for backwards compatibility. See wiki.bash-hackers.org/scripting/obsolete — Charles Duffy
– Charles Duffy, Commented Apr 10, 2018 at 19:58
Ideally, you should be using lowercase names for your own variables. See pubs.opengroup.org/onlinepubs/9699919799/basedefs/…, fourth paragraph -- all caps names are used for variables meaningful to the shell or operating system, whereas lowercase names are reserved for application use. — Charles Duffy
– Charles Duffy, Commented Apr 10, 2018 at 19:58

glenn jackman · Accepted Answer · 2018-04-10 19:50:47Z

0

You are putting the code in double quotes, so the variables and commands are being executed on your local machine. Do echo "$MYFUNCTION" and you'll probably be surprised.

Try using a quoted here document:

# Note the single quotes in the next line
ssh -l "$USERNAME" "$HOSTNAME" <<'END_CODE'
function my_function
{
    cd www
    VAR=$(readlink -f current | sed 's/[^0-9]*//g')
    VAR2=$(find . -maxdepth 1 ! -newer "$VAR" ! -name "$VAR"| sort | sed '$!d')
}
my_function
END_CODE

Note also all the quoted variables.

answered Apr 10, 2018 at 19:50

glenn jackman

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