How do I read an entire InputStream into a byte array?
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18See the reverse: byte[] to InputStream here: stackoverflow.com/questions/2091454/…David d C e Freitas– David d C e Freitas2011-09-22 10:34:53 +00:00Commented Sep 22, 2011 at 10:34
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35 Answers
/*InputStream class_InputStream = null;
I am reading class from DB
class_InputStream = rs.getBinaryStream(1);
Your Input stream could be from any source
*/
int thisLine;
ByteArrayOutputStream bos = new ByteArrayOutputStream();
while ((thisLine = class_InputStream.read()) != -1) {
bos.write(thisLine);
}
bos.flush();
byte [] yourBytes = bos.toByteArray();
/*Don't forget in the finally block to close ByteArrayOutputStream & InputStream
In my case the IS is from resultset so just closing the rs will do it*/
if (bos != null){
bos.close();
}
1 Comment
akostadinov
Closing and flushing bos is a waste of keyboard clicks. Closing the input stream is more likely to help. Reading one byte at a time is inefficient. See numan's answer.
This works for me,
if(inputStream != null){
ByteArrayOutputStream contentStream = readSourceContent(inputStream);
String stringContent = contentStream.toString();
byte[] byteArr = encodeString(stringContent);
}
readSourceContent()
public static ByteArrayOutputStream readSourceContent(InputStream inputStream) throws IOException {
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
int nextChar;
try {
while ((nextChar = inputStream.read()) != -1) {
outputStream.write(nextChar);
}
outputStream.flush();
} catch (IOException e) {
throw new IOException("Exception occurred while reading content", e);
}
return outputStream;
}
encodeString()
public static byte[] encodeString(String content) throws UnsupportedEncodingException {
byte[] bytes;
try {
bytes = content.getBytes();
} catch (UnsupportedEncodingException e) {
String msg = ENCODING + " is unsupported encoding type";
log.error(msg,e);
throw new UnsupportedEncodingException(msg, e);
}
return bytes;
}
1 Comment
Thomas Perl
Why convert to
String and then to byte[] (which might mess with binary data)? ByteArrayOutputStream has .toByteArray(): docs.oracle.com/javase/7/docs/api/java/io/…Java 7 and later:
import sun.misc.IOUtils;
...
InputStream in = ...;
byte[] buf = IOUtils.readFully(in, -1, false);
1 Comment
Holger
sun.misc.IOUtils is not “Java 7”. It’s a proprietary, implementation specific class that may not be present in other JRE implementations and can disappear without any warning in one of the next releases.For Android developers dealing with the inter-op between Java and Kotlin:
byte[] myByteArray = ByteStreamsKt.readBytes(fileInputStream);
Comments
Below Codes
public static byte[] serializeObj(Object obj) throws IOException {
ByteArrayOutputStream baOStream = new ByteArrayOutputStream();
ObjectOutputStream objOStream = new ObjectOutputStream(baOStream);
objOStream.writeObject(obj);
objOStream.flush();
objOStream.close();
return baOStream.toByteArray();
}
OR
BufferedImage img = ...
ByteArrayOutputStream baos = new ByteArrayOutputStream(1000);
ImageIO.write(img, "jpeg", baos);
baos.flush();
byte[] result = baos.toByteArray();
baos.close();
