Sorting Python dictionary based on nested dictionary values

Question

How do you sort a Python dictionary based on the inner value of a nested dictionary?

For example, sort mydict below based on the value of context:

mydict = {
    'age': {'context': 2},
    'address': {'context': 4},
    'name': {'context': 1}
}

The result should be like this:

{
    'name': {'context': 1}, 
    'age': {'context': 2},
    'address': {'context': 4}       
}

Do you want a list output? or a dictionary output?

Deniz
– Deniz

2012-08-01 06:34:16 +00:00
Commented Aug 1, 2012 at 6:34 — Deniz
– Deniz, Commented Aug 1, 2012 at 6:34

jamylak · Accepted Answer · 2012-08-01 06:31:10Z

21

>>> from collections import OrderedDict
>>> mydict = {
        'age': {'context': 2},
        'address': {'context': 4},
        'name': {'context': 1}
}
>>> OrderedDict(sorted(mydict.iteritems(), key=lambda x: x[1]['context']))
OrderedDict([('name', {'context': 1}), ('age', {'context': 2}), ('address', {'context': 4})])

answered Aug 1, 2012 at 6:31

jamylak

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