Data Structure in array NullPointerException [duplicate]

Question

Possible Duplicate:
NullPointerException when Creating an array of object

I am having NullPointerException in main method, in line

array[0].name = "blue";

Structure Class:

public class Items {

String name = "";
String disc = "";
}

Main Class :

public class ItemsTest {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        Items[] array = new Items[2];

            array[0].name = "blue"; //NullPointerException
        array[0].disc = "make";
        array[1].name = "blue";
        array[1].disc = "blue";
           }
}

Please help me how to resolve this.

Another one: stackoverflow.com/questions/4067286/…

Lukas Eder
– Lukas Eder

2012-07-18 09:56:22 +00:00
Commented Jul 18, 2012 at 9:56 — Lukas Eder
– Lukas Eder, Commented Jul 18, 2012 at 9:56
Another one: stackoverflow.com/questions/8145728/…

Lukas Eder
– Lukas Eder

2012-07-18 09:58:42 +00:00
Commented Jul 18, 2012 at 9:58 — Lukas Eder
– Lukas Eder, Commented Jul 18, 2012 at 9:58

Jigar Joshi · Accepted Answer · 2012-07-18 09:55:19Z

2

Items[] array = new Items[2];

You have to initialize each element of array, by default they are null

Make it,

Items[] array = new Items[2];
//initialization
array[0] = new Items();
array[0].name = "blue"; //NullPointerException
array[0].disc = "make";

//initialization
array[1] = new Items();
array[1].name = "blue";
array[1].disc = "blue";

answered Jul 18, 2012 at 9:55

Jigar Joshi

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Community · Accepted Answer · 2017-05-23 11:51:54Z

1

When you wrote the line:

Items[] array = new Items[2];

You initialized an Array of the type Items which can contain 2 elements, or in other words, you only initialized the container.

Each element in the array is an object and also needs initialization, and when addressing array[0].name you're trying to access the inner element which is currently null If you'll check Jigar Joshi answer, you'll see he also initializes each Items element inside the array.

Hope this helps!

edited May 23, 2017 at 11:51

CommunityBot

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answered Jul 18, 2012 at 11:49

Meny Issakov

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Comments

Lukas Eder · Accepted Answer · 2012-07-18 11:48:45Z

0

Items[] array = new Items[2]; // Creates an array of Items with null values

Hence have to use

Items[] array = { new Items(), new Items() }; // as suggested by aioobe....

or need to intialise the array like

array[0] = new Items();

edited Jul 18, 2012 at 11:48

Lukas Eder

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answered Jul 18, 2012 at 10:12

kartheek

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