java.util.stream.IntStream/LongStream | Search an element

Given an array of elements of integers or long data type, you need to check if a given key is present in this array using pre defined functions in java.util.stream.IntStream. The java.util.stream.IntStream/LongStream class contains a function anyMatch(), which helps to check if a particular element is present in an array. Examples:

Input : arr[] = {1,2,3,4,5,6,7} ,  key = 3
Output : Yes
         3 is present in the array.

Input : arr[] = {1,2,3,4,5,6,7} ,  key = 8
Output : No

The Stream.anyMatch() method is used to check if the stream contains any such element which matches with a given predicate. It will return true if atleast 1 of the elements of the stream matches with the given predicate condition otherwise it will return false. Syntax:

boolean anyMatch(Predicate< ? super T >  predicate)

Below is a Java program on how to use anyMatch() method with both integer stream and stream of long integers. Java

// Java program to check if an element is present
// in an array using java.util.stream.IntStream

import java.util.stream.IntStream;
import java.util.stream.LongStream;

class CheckElement
{
    public static void main (String[] args) 
    {   
        // stream of integer
        int num[] = {1,2,3,4,5,6,7};
        
        int key = 3;  // key to be searched
        boolean result = IntStream.of(num).anyMatch(x -> x == key);
        if (result)
            System.out.println("Yes");
        else
            System.out.println("No");
        
        // stream of long
        long lnum[] = {1,2,3,4,5,6,7};

        // key to be searched
        long lkey = 7;
        boolean result2 = LongStream.of(lnum).anyMatch(x -> x == lkey);
        if (result2)
            System.out.println("Yes");
        else
            System.out.println("No");
    }
}

Output:

Yes
Yes

Reference: anyMatch() java docs