#echo $LINE |cut -f"${arg}" -d' '
pom=$LINE |cut -f"${arg}" -d' '
I have this two lane. First is working but second not. I want to variable get a value of this command cuz i want use this value like string.
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3 Answers
You need to run the first line, then assign the value returned to the variable. You do this with the command inside backticks, like this:
pom=`echo $LINE |cut -f"${arg}" -d' '`
The reason the second line doesn't work, is because whats in $LINE is most probably not a valid command, and pipes takes outputs from commands, which is why you need echo to output the contents of $LINE.
answered Nov 7, 2011 at 9:26
Some programmer dude
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This kind of code is discouraged :
pom=`echo $LINE |cut -f"${arg}" -d' '`
in favor of :
pom=$(echo "$LINE" | cut -f"${arg}" -d' ')
The backquote () is used in the old-style command substitution, e.g. foo=command`. The foo=$(command) syntax is recommended instead. Backslash handling inside $() is less surprising, and $() is easier to nest. See http://mywiki.wooledge.org/BashFAQ/082
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If there are no empty fields in LINE (i.e. no repeated spaces), you can also use pure bash:
ITEMS=($LINE)
pom=${ITEMS[arg]}
Note that $arg is zero based in this case, so you might need to use [arg-1].
