Check an array of strings against another array - Bash

Question

I have two lists.

I have to check if there is a tar.gz which name contains a substring like aa or ab and so on. I'm using this little function: How do you tell if a string contains another string in POSIX sh?

local=(aa ab ac ad ae)
remote=(ab.tar.gz ac.tar.gz ad.tar.gz ae.tar.gz af.tar.gz)

contains() { test -n "$1" || test -z "$2" && test -z "${1##*"$2"*}"; }
for le in "${local[@]}"; do
    for re in "${remote[@]}"; do
        contains "$re" "$le" && to_dl+=("$re")
    done
done

This works well for me, but I need a second list, which contains the elements of the local list, that don't have a match in the remote list.

What do you want to achieve with the list? where is the second list? — Jetchisel
– Jetchisel, Commented Jun 12, 2023 at 8:26
please update the question with the current output and the desired output — markp-fuso
– markp-fuso, Commented Jun 12, 2023 at 11:39

markp-fuso · Accepted Answer · 2023-06-12 14:26:21Z

0

Small modification to OP's current code:

local=(aa ab ac ad ae)
remote=(ab.tar.gz ac.tar.gz ad.tar.gz ae.tar.gz af.tar.gz)

unset to_dl not_there           # or: to_dl=() not_there=()

contains() { test -n "$1" || test -z "$2" && test -z "${1##*"$2"*}"; }

for le in "${local[@]}"
do
    for re in "${remote[@]}"
    do
        contains "$re" "$le" && { to_dl+=("$re"); continue 2; }
    done
    not_there+=("$le")
done

Where:

continue 2 - if we find a match then skip to the next substring (le) in the list
not_there+=("$le") - if inner loop finds no matches then save the substring in a different array

Results:

$ typeset -p to_dl not_there
declare -a to_dl=([0]="ab.tar.gz" [1]="ac.tar.gz" [2]="ad.tar.gz" [3]="ae.tar.gz")
declare -a not_there=([0]="aa")

edited Jun 12, 2023 at 14:26

answered Jun 12, 2023 at 14:14

markp-fuso

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Comments

KamilCuk · Accepted Answer · 2023-06-12 08:38:01Z

0

Consider just grep -f.

$ tmp=$(printf "%s\n" "${remote[@]}" | grep -Ff <(printf "%s\n" "${local[@]}"))
$ readarray -t to_dl <<<"$tmp"
$ declare -p to_dl
declare -a to_dl=([0]="ab.tar.gz" [1]="ac.tar.gz" [2]="ad.tar.gz" [3]="ae.tar.gz")

I need a second list, which contains the elements of the local list, that don't have a match in the remote list.

Use grep -v.

In your code, just use if. Overall, prefer if over any &&.

if contains "$re" "$le"; then
    to_dl+=("$re")
else
    secondlist+=("$re")
fi

edited Jun 12, 2023 at 8:38

answered Jun 12, 2023 at 8:28

KamilCuk

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1 Comment

michel Over a year ago

Thank you, @KamilCuk. Maybe my example or explanation is bad. local=(aa ab ac ad ae ag) remote=(ab.tar.gz ac.tar.gz ad.tar.gz ae.tar.gz af.tar.gz) Result should be: to_dl=(ab.tar.gz ac.tar.gz ad.tar.gz ae.tar.gz) not_there=(aa ag)

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