typescript check object is not empty with any object definition

Question

Here is my current code:

interface ObjectIsEmptyProps {
  [index: string]: number | string;
}
export const objectIsEmpty = (a: ObjectIsEmptyProps) => a &&  
Object.keys(a).length >

I need to check an object that might have any number properties provided to it. So 3 examples of possible function calls are:

objectIsEmpty({}) //true
objectIsEmpty({ jamie: 'hutber' }) //false
objectIsEmpty({fank: 'skinner', jamie: 'hutber' }) //false
objectIsEmpty({anArray: [], aBoolie: false, chickenSkin: 'isGreat'}) //false

So my function can take an object with an undetermined set of properties. Currently the only way I can TS to be happy is to use any as the type of the argument.

How can I support any number of object properties without using any?

Thanks for taking the time to look at the question! Could I please get some feedback on how to improve the question after the downvote. Thanks — Jamie Hutber
– Jamie Hutber, Commented Jun 22, 2022 at 7:37
The issue will still exist that I cannot define the types of the function to accept any shaped object. — Jamie Hutber
– Jamie Hutber, Commented Jun 22, 2022 at 7:44
Not sure what you mean by that, however here are some ways stackoverflow.com/questions/2673121/… — Murat Karagöz
– Murat Karagöz, Commented Jun 22, 2022 at 7:45
Have updated with more clear examples of what I need it to do. — Jamie Hutber
– Jamie Hutber, Commented Jun 22, 2022 at 19:41

André Krosby · Accepted Answer · 2022-06-22 07:54:17Z

1

I'm not sure I fully understand the question. However, could you use the Record utility?

export const objectIsEmpty = (a: Record<string, unknown>) => {
  return Object.keys(a).length === 0
}

answered Jun 22, 2022 at 7:54

André Krosby

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