initialization for array of arrays in PHP

Question

I want to dynamically create arrays of arrays and I have no clue how to initialize my arrays...

Here is the code:

$resT= array();
$resR= array();
foreach ($cursor as $obj) {
   if ($obj == NULL) continue;
   $c="XX";
   if (test1)         $c=$obj['GC'];
   array_push($resT[$c],$obj['AT']);
   array_push($resR[$c],$obj['AR']);
}

I got this: array_push() expects parameter 1 to be array

Thanks,

Amir.

You should use other variable names: $resT, $resR, $obj and so on are not very useful names. A variable name should always speak for itself. — KingCrunch
– KingCrunch, Commented Jul 19, 2011 at 21:17

Paul · Accepted Answer · 2011-07-19 21:16:43Z

2

$resT= array();
$resR= array();
foreach ($cursor as $obj) {
   if ($obj == NULL) continue;
   $c="XX";
   if (test1)         $c=$obj['GC'];
    if(!isset($resT[$c]))
      $resT[$c] = array();
    if(!isset($resR[$c]))
      $resR[$c] = array();
   array_push($resT[$c],$obj['AT']);
   array_push($resR[$c],$obj['AR']);
}

answered Jul 19, 2011 at 21:16

Paul

142k28 gold badges285 silver badges272 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Amir Over a year ago

Thanks, It worked... I am newbie... I didn't know about isset() function.

Dan · Accepted Answer · 2011-07-19 21:16:55Z

1

You don't even need to use array_push.

You can use the shorthand notation of

$resT= array();
$resR= array();
foreach ($cursor as $obj) {
   if ($obj == NULL) continue;
   $c="XX";
   if (test1)         $c=$obj['GC'];
   $resT[$c] = array();
   $resT[$c][] = $obj['AT'];
   $resR[$c] = array();
   $resR[$c][] = $obj['AR'];
}

answered Jul 19, 2011 at 21:16

Dan

191 bronze badge

1 Comment

KingCrunch Over a year ago

You re-create $resT[$c] ($resR[$c] respectively) in every iteration. This means every $resT[$c] contains only the last element for every value of $c.

Karl Laurentius Roos · Accepted Answer · 2011-07-19 21:16:48Z

0

I have no idea what you're trying to accomplish but this should resolve your PHP notice at least:

$resT= array();
$resR= array();
foreach ($cursor as $obj) {
   if ($obj == NULL) continue;
   $c="XX";
   if (test1)         $c=$obj['GC'];

   if(!is_array($resT[$c])){
      $resT[$c] = array();
   }

   if(!is_array($resR[$c])){
      $resR[$c] = array();
   }

   array_push($resT[$c],$obj['AT']);
   array_push($resR[$c],$obj['AR']);
}

answered Jul 19, 2011 at 21:16

Karl Laurentius Roos

4,4391 gold badge35 silver badges42 bronze badges

Comments

KingCrunch · Accepted Answer · 2011-07-19 21:21:34Z

0

$resT= array();
foreach ($cursor as $obj) {
  if (!is_null($obj)) {
    $c = $test1 ? $obj['GC'] : "XX";
    if (!array_key_exists($c, $resT)) $resT[$c] = array();
    $resT[$c][] = $obj['AT'];
  }
}
$resR = $resT;

answered Jul 19, 2011 at 21:21

KingCrunch

133k22 gold badges158 silver badges174 bronze badges

Collectives™ on Stack Overflow

initialization for array of arrays in PHP

4 Answers 4

1 Comment

1 Comment

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

1 Comment

1 Comment

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related