How to convert XML to Json with binary data content

Question

I try to convert from xml to json. It work well with normal text data content. When the data in a xml tag is a binary, we can not unmarshal the xml to java object. Can you help to share how we convert from xml to json for binary.

Java Code:

public <T> String xmlToJson(Class<T> clazz, String xmlString, boolean includeRoot) throws CustomException {
    StringWriter writer = new StringWriter();
    String jsonString = "{}";

    try {

        XMLInputFactory xif = XMLInputFactory.newInstance();
        xif.setProperty(XMLInputFactory.IS_SUPPORTING_EXTERNAL_ENTITIES, false);
        xif.setProperty(XMLInputFactory.SUPPORT_DTD, true);
        XMLStreamReader xsr = xif.createXMLStreamReader(new StringReader(xmlString));
        JAXBContext jc = JAXBContext.newInstance(clazz);
        Unmarshaller unmarshaller = jc.createUnmarshaller();
        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.setProperty("eclipselink.media-type", "application/json");
        marshaller.setProperty("eclipselink.json.include-root", includeRoot);
        marshaller.setProperty(MarshallerProperties.JSON_ATTRIBUTE_PREFIX, "@");
        JAXBElement<T> addressFromXML = unmarshaller.unmarshal(xsr, clazz); //ERROR at this line for binary data
        marshaller.marshal(addressFromXML, writer);
        jsonString = writer.toString();
    } catch (Exception e) {
        logger.error(e.getMessage());
        throw new CustomException(e.getMessage());
    }
    return jsonString;
}

Here is the error:

Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Handler dispatch failed; nested exception is java.lang.NoClassDefFoundError: javax/mail/internet/MimeMultipart] with root cause
java.lang.NoClassDefFoundError: javax/mail/internet/MimeMultipart
    at org.eclipse.persistence.internal.oxm.XMLBinaryDataHelper.initializeDataTypes(XMLBinaryDataHelper.java:74)
    at org.eclipse.persistence.internal.oxm.XMLBinaryDataHelper.<init>(XMLBinaryDataHelper.java:54)
    at org.eclipse.persistence.internal.oxm.XMLBinaryDataHelper.getXMLBinaryDataHelper(XMLBinaryDataHelper.java:60)
    at org.eclipse.persistence.internal.oxm.XMLInlineBinaryHandler.endElement(XMLInlineBinaryHandler.java:126)
    at org.eclipse.persistence.internal.oxm.record.deferred.EndElementEvent.processEvent(EndElementEvent.java:37)
    at org.eclipse.persistence.internal.oxm.record.deferred.DeferredContentHandler.executeEvents(DeferredContentHandler.java:64)
    at org.eclipse.persistence.internal.oxm.record.deferred.BinaryMappingContentHandler.executeEvents(BinaryMappingContentHandler.java:75)
    at org.eclipse.persistence.internal.oxm.record.deferred.BinaryMappingContentHandler.processSimpleElement(BinaryMappingContentHandler.java:67)
    at org.eclipse.persistence.internal.oxm.record.deferred.DeferredContentHandler.endElement(DeferredContentHandler.java:122)
    at org.eclipse.persistence.internal.oxm.record.XMLStreamReaderReader.parseEvent(XMLStreamReaderReader.java:150)
    at org.eclipse.persistence.internal.oxm.record.XMLStreamReaderReader.parse(XMLStreamReaderReader.java:100)
    at org.eclipse.persistence.internal.oxm.record.XMLStreamReaderReader.parse(XMLStreamReaderReader.java:87)
    at org.eclipse.persistence.internal.oxm.record.SAXUnmarshaller.unmarshal(SAXUnmarshaller.java:1016)
    at org.eclipse.persistence.internal.oxm.XMLUnmarshaller.unmarshal(XMLUnmarshaller.java:657)
    at org.eclipse.persistence.jaxb.JAXBUnmarshaller.unmarshal(JAXBUnmarshaller.java:460)

But it fail for binary data content - and where is error? It would help if you don't swallow exception in try/catch block ... — rkosegi
– rkosegi, Commented Jan 8, 2021 at 7:01
Hi @rkosegi, I have just update my question which include the stack trace. This is the first time I try to parse xml with binary content to object and from object to json. — John
– John, Commented Jan 8, 2021 at 7:12
<xs:element name="content" minOccurs="0"> <xs:annotation> <xs:documentation>binary content</xs:documentation> </xs:annotation> <xs:simpleType> <xs:restriction base="xs:base64Binary"> </xs:restriction> </xs:simpleType> </xs:element> — John
– John, Commented Jan 8, 2021 at 7:13
Underscore-java library has a static method U.xmlToJson(xmlstring). — Valentyn Kolesnikov
– Valentyn Kolesnikov, Commented Feb 21, 2021 at 8:59

rkosegi · Accepted Answer · 2021-01-08 07:14:34Z

1

java.lang.NoClassDefFoundError: javax/mail/internet/MimeMultipart

You are missing java mail-api on your classpath.

If you're using maven, you should be able to fix that be adding floowing dependencies:

    <dependency>
        <groupId>javax.mail</groupId>
        <artifactId>javax.mail-api</artifactId>
    </dependency>
    <dependency>
        <groupId>com.sun.mail</groupId>
        <artifactId>javax.mail</artifactId>
    </dependency>

More information about Java Mail API

answered Jan 8, 2021 at 7:14

rkosegi

14.8k5 gold badges57 silver badges90 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

John Over a year ago

Thank rkosegi. It is working well. I still not understand why javax.mail will relate to unmarshal from xml to object. Can you help to explain?

John Over a year ago

After I add library <dependency> <groupId>javax.mail</groupId> <artifactId>javax.mail-api</artifactId> <version>1.6.2</version> </dependency>

rkosegi Over a year ago

@John java mail API is transitively required by eclipselink

John Over a year ago

Thank a lot. now I understood. For text data, it not call to third party libs. For binary data, it call to third party libs (javax.mail-api) to handle parser. Thank for your explanation.

Collectives™ on Stack Overflow

How to convert XML to Json with binary data content

1 Answer 1

4 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

4 Comments

Your Answer

Sign up or log in

Post as a guest

Related