How grouped sort array of objects based on object's value?

Question

I have array of objects like this:

var points = [{a: 4, b: 3, c:'parent'}, {a: 1, b:5, c:'child'}, {a: 5, b: 2, c:'child'}, {a: 1, b: 2, c:'parent'}, {a: 3, b: 1, c:'child'}];

I need to sort it on "a" object's value. But the problem is if it has the "c" object's value "parent" the "c" object's value "child" should be next object of that and shouldn't be sorted.

At last I expect to have this sorted points array:

var sortedPoints = [{a: 1, b: 2, c:'parent'}, {a: 3, b: 1, c:'child'} ,{a: 4, b: 3, c:'parent'}, {a: 1, b:5, c:'child'}, {a: 5, b: 2, c:'child'}];

Nina Scholz · Accepted Answer · 2020-08-20 11:43:43Z

1

You need to group parents and children, sort and get a flat array.

var points = [{ a: 4, b: 3, c: 'parent' }, { a: 1, b: 5, c: 'child' }, { a: 5, b: 2, c: 'child' }, { a: 1, b: 2, c: 'parent' }, { a: 3, b: 1, c: 'child' }],
    sorted = points
        .reduce((r, o) => {
            if (o.c === 'parent') r.push([o]);
            else r[r.length - 1].push(o);
            return r;
        }, [])
        .sort(([{ a }], [{ a: b }]) => a - b)
        .flat();

console.log(sorted);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Aug 20, 2020 at 11:43

Nina Scholz

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2 Comments

Atousa Darabi Over a year ago

You did it exactly on "a" and "b" object. What should I do for sorting if I have so many more keys on array's objects?

Nina Scholz Over a year ago

just take .sort(a, b) => ...) and get the needed properties from a and b without destructuring.

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