Create an array of objects by splitting a string

Question

I have string that input from user like this var str="aa bb cc"

Can I need like this

mylists = [ 
           { "0": "11", "1": "aa" }, 
           { "0": "aa", "1": "bb" }, 
           { "0": "bb", "1": "cc" }, 
           { "0": "cc", "1": "11" }, .... 
          ]`

Note: first and last value must be 11

this is the code I have tried

var str =$("#gettxt").val(); //my value get from user input`

console.log(str );
var parts = str.split(" ");
var numpro =countString(str); //i have other function count word in string that user input
tbl+="";
var listt = [];
for (i = 0; i < numpro; i++) {
    listt.push({
        0:"11",
        1:parts[i]
    })
}
console.log(listt)

What is the output of the code, which you have tried?

Tushar
– Tushar

2020-07-28 04:48:06 +00:00
Commented Jul 28, 2020 at 4:48 — Tushar
– Tushar, Commented Jul 28, 2020 at 4:48

Nick · Accepted Answer · 2020-07-28 04:50:54Z

1

After splitting your string, you can add a leading and trailing 11 to the array, and then make up each object from the current and next element in the array:

// user input string
var str="aa bb cc"

// split and add leading and trailing `11`
var parts = ['11'].concat(str.split(" ")).concat('11');
var numpro = parts.length;
var listt = [];
for (i = 0; i < numpro-1; i++) {
    listt.push({
        0:parts[i],
        1:parts[i+1]
    })
}
console.log(listt)

answered Jul 28, 2020 at 4:50

Nick

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Comments

Sven.hig · Accepted Answer · 2020-07-28 05:00:33Z

1

You could split the array unshift() 11 always to be at the beginning of the array and then use map

var str="aa bb cc"
arr=str.split(" ")
arr.unshift("11")
res=arr.map((n,i)=>({"0":n,"1":arr[i+1]||"11"}))
console.log(res)

answered Jul 28, 2020 at 5:00

Sven.hig

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1 Comment

Sven.hig Over a year ago

You' re Welcome, conceder upvoting and accepting my answer if it helped you :)

adiga · Accepted Answer · 2020-07-28 05:15:14Z

1

You could create an array by splitting the string and adding "11" at the beginning and the end. Then create an array using Array.from() and spread a chunk of the array inside the {} to create an object with numeric indices.

const str = "aa bb cc",
      parts = ["11", ...str.split(" "), "11"],
      length = parts.length - 1,
      output = Array.from({ length }, (_, i) => ({ ...parts.slice(i, i+2) }))

console.log(output)

answered Jul 28, 2020 at 5:15

adiga

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Comments

Siva Kondapi Venkata · Accepted Answer · 2020-07-28 08:24:45Z

1

Using map and split in one line

const getArray = (str, fill = "11") =>
  [...str.split(" "), fill].map((x, i, arr) => ({
    0: arr[i - 1] ?? fill,
    1: x,
  }));

var str = "aa bb cc";
console.log(getArray(str));

edited Jul 28, 2020 at 8:24

answered Jul 28, 2020 at 7:09

Siva Kondapi Venkata

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Comments

Unmitigated · Accepted Answer · 2020-07-28 04:50:43Z

0

You can use Array#map with an additional push call at the end.

let parts = str.split(' ');
let res = parts.map((x,idx)=>({0: idx === 0 ? "11" : parts[idx - 1], 1: x}));
res.push({0: parts[parts.length - 1], 1: "11"});

The additional push at the end can be avoided by appending " 11" to the string before splitting.

let parts = (str + " 11").split(' ');
let res = parts.map((x,idx)=>({0: idx === 0 ? "11" : parts[idx - 1], 1: x}));

answered Jul 28, 2020 at 4:50

Unmitigated

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