Typescript export default: React.FunctionComponent

Question

How would I go about this in typescript. I know I can do it with giving it a name but thats not what I'm asking. I'm asking how can I still just use default.

interface IProps {
  name: string,
  tag: string,
}

export default ({name, tag}: IProps) => {
 ..... my code 
});

Yes I know about this.

const MyComponent: React.FunctionComponent = () => {
...
export default MyComponent;

Mulan · Accepted Answer · 2020-06-02 22:52:49Z

3

Um, exactly like you have it, except for the trailing ) syntax error

import React from "react"

interface IProps {
  name: string,
  tag: string,
}

export default ({name, tag}: IProps): JSX.Element => {
  return <p>hello { name }, some { tag }</p>
} // <- no trailing `)`

Or -

import React from "react"

interface IProps {
  name: string,
  tag: string,
}

export default ({name, tag}: IProps): JSX.Element =>
  <p>hello { name }, some { tag }</p>

TypeScript Playground Demo

That said, a named function is much better, especially for debugging purposes.

edited Jun 2, 2020 at 22:52

answered Jun 2, 2020 at 22:46

Mulan

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3 Comments

me-me Over a year ago

So you wouldn't use React.FunctionComponent instead of JSX.Element ? Thanks for the help :)

Alex Wayne Over a year ago

@me-me Yep, a functional component is just one that accepts props as an object, and returns JSX compatible content. All you need to do is conform to that expectation.

Mulan Over a year ago

@me-me, there's a subtle difference using React.FunctionComponent. I personally don't see the gain unless you are trying to enforce a very specific constraint.

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