how to check digits present in javascript string or not

Question

I need a regex which check the string contains only A-Z, a-z and special characters but not digits i.e. (0-9). Any help is appreciated.

hsz · Accepted Answer · 2011-05-31 13:01:07Z

6

You can try with this regex:

^[^\d]*$

And sample:

var str = 'test123';
if ( str.match(/^[^\d]*$/) ) {
  alert('matches');
}

answered May 31, 2011 at 13:01

hsz

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2 Comments

hsz Over a year ago

Also ^\d equals \D so you can use: ^\D*$

Salil Over a year ago

thanks for additional info, it works for me so upvote it.i didn't check for other answers as of now so will accept only after checking all the answers

Gareth · Accepted Answer · 2011-05-31 13:09:36Z

3

Simple:

/^\D*$/

It means, any number of not-a-digit characters. See it in action…

The alternative is to reverse your test. Just check if there's a digit present, using the trivial:

/\d/

…and if that matches, your string fails.

answered May 31, 2011 at 13:09

Gareth

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1 Comment

Jonathon Over a year ago

The second regex should be slightly more efficient and is as far as I can tell the best answer.

SLaks · Accepted Answer · 2011-05-31 13:01:32Z

0

You're looking for a character class: ^[A-Za-z.,!@#$%^&*()=+_-]+$.

The ^ and $ anchor the regex by marching the beginning and end of the string, respectively.

answered May 31, 2011 at 13:01

SLaks

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Comments

Toto · Accepted Answer · 2011-05-31 13:01:48Z

0

what about:

var re = /^[a-zA-Z!#$%]+$/;

Fell free to add any special character you need inside the character class

answered May 31, 2011 at 13:01

Toto

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