sort function in python for loop doesn't repeat

Question

n = int(input())
string = input()
string_list = list(string)

division_list = []
for i in range(n):
    if n%(i+1) == 0:
        division_list.append(i+1)
division_list.sort(reverse=True)
print(division_list)

for division in division_list:
    temp1 = string_list[:division]
    temp2 = string_list[division:]
    print('before reverse')
    print(temp1)
    temp1.sort(reverse=True)
    print('after reverse')
    print(temp1)
    string_list = temp1 + temp2

ans = ''.join(string_list)
print(ans)

I was solving problem in code forces, and realized sort function doesn't work more than one in for loop. Why? And is there any further stuffs I can do on my code?
This is the link of the question.
https://codeforces.com/problemset/problem/999/B

edited) I put 4 and abcd as a input. This is the output. I expected to see ['c', 'd'] after second temp1.sort(reverse=True). But it doesn't reversed.

4
abcd
[4, 2, 1]
before reverse
['a', 'b', 'c', 'd']
after reverse
['d', 'c', 'b', 'a']
before reverse
['d', 'c']
after reverse
['d', 'c']
before reverse
['d']
after reverse
['d']
dcba

What do you mean by "sort function doesn't work more than one in for loop"? Can you show the specific problem you're having? — dspencer
– dspencer, Commented Apr 3, 2020 at 3:56
Can you give an example of input where you get output you don't expect? And describe what you expect and what you get instead? — Blckknght
– Blckknght, Commented Apr 3, 2020 at 4:06
@dspencer If you run this code, you'll see temp1.sort(reverse=True) function won't work from second for loop. I do test with 4 for 1st input abcd for 2nd input — lcpnine
– lcpnine, Commented Apr 3, 2020 at 4:07
Make it easy for us, we shouldn't have to run the code to see your problem - please indicate in the question exactly what isn't working as you expect. — dspencer
– dspencer, Commented Apr 3, 2020 at 4:08
In all the cases after the first, the list happened to already be in reverse order - there wasn't anything for .sort() to do. If you wanted to reverse whatever order the list happened to have, that's not a job for .sort(), that's temp1 = temp1[::-1]. — jasonharper
– jasonharper, Commented Apr 3, 2020 at 4:13

Monty _s Flying Circus · Accepted Answer · 2020-04-03 04:59:11Z

2

Python .sort function sorts the list in ascending order. What the reverse parameter does is reverses the sorted list; so in this case in descending order, which happens to be the original list.

If you are trying to reverse the list I think temp1.reverse() would work (https://www.geeksforgeeks.org/python-list-reverse/). Otherwise, you could do something like this:

temp1 = temp1[::-1]

edited Apr 3, 2020 at 4:59

Monty _s Flying Circus

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answered Apr 3, 2020 at 4:51

msche

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