How to filter array by array of dynamic objects?

Question

i have a huge collection of data 700+ items in, and i want to filter by dynamic array of objects, lets say that user has typed ode and my script should search on every filter without i do something like filter.code == store.code

const hugeData = [{name:"store 1",code : "code 1", available : false},{name : "store 2",code : "simple_code",available : true},{name : "sto 3",code : "has no cde",available : true}...]

const filters = [{ code : "ode", name : "re" }]

the result that im expecting is

// output
[{name : "store 1", code : "code 1", available : false},{name : "store 2",code : "simple_code",available : true}]

i resolved this doing the following with lodash, but function is very slow, and code is poor, is there any other way that i can do this works?

const results = []
_.map(hugeData, store => {
    _.map(filters, tag => {
        Object.keys(tag).map(tagOb => {
          if (store[tagOb] && store[tagOb].includes(tag[tagOb])) {
             results.push(store);
          }
        });
    });
});

couldn't filters just be a single object of key value pairs? why would it need to be in an array? — Anthony
– Anthony, Commented Oct 27, 2019 at 3:01
@Anthony yes, i can modify it, but if its a simple object, how that should work? — Dante Cervantes
– Dante Cervantes, Commented Oct 27, 2019 at 3:02
@Anthony not all have to match, with only one that matches, result should appear — Dante Cervantes
– Dante Cervantes, Commented Oct 27, 2019 at 3:06

Code Maniac · Accepted Answer · 2019-10-27 03:10:05Z

3

You can use filter and some

const hugeData = [{ name: "store 1", code: "code 1",available: false}, { name: "store 2", code: "simple_code",available: true}, { name: "sto 3", code: "has no cde", available: true }]

const filters = { code: "ode", name: "re" }

let final = hugeData.filter(value => {
  return Object.entries(value).some(([key, value]) => {
    return typeof value == 'string' && value.includes(filters[key])
  })
})

console.log(final)

answered Oct 27, 2019 at 3:10

Code Maniac

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Comments

Anthony · Accepted Answer · 2019-10-27 03:14:38Z

0

This might be faster - storing the Object.keys() result, and filtering out any keys that aren't on the first store (assuming all stores are equivalent). I also used a single object for filters.

const hugeData = [
  { name: "store 1", code: "code 1", available: false },
  { name: "store 2", code: "simple_code", available: true },
  { name: "sto 3", code: "has no cde", available: true }
];

const filters = { code: "ode", name: "re" };
const keys = Object.keys(filters).filter(k => hugeData[0].hasOwnProperty(k));

console.log(
  hugeData.filter(s => keys.some(k => s[k].includes(filters[k])))
);

If you wanted ALL filters, to match, you could change it to every:

hugeData.filter(s => keys.every(k => s[k].includes(filters[k])))

edited Oct 27, 2019 at 3:14

answered Oct 27, 2019 at 3:07

Anthony

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