Search in arrays with for loop using JavaScript

Question

I have to search in array items using for loop without any "method", "function" or "break" syntax. I wrote this code bud does not work!

var array = [12, "Data", true, "S"]

var searchItem = "Data"

var i

for (i = 0; i < array.length; i++) {
    if (array[i] == searchItem) {
        console.log("Item Found")
    } else {
        console.log("Item Not Found")
    }
}

This will be print: Item Not Found Item Found Item Not Found Item Not Found — user10588443
– user10588443, Commented Oct 31, 2018 at 23:09
@MasoodSadri Even when you click "Run code snippet", it works:) It does so because you want to log something to the console on every iteration. — tera_789
– tera_789, Commented Oct 31, 2018 at 23:09
It does't work! I mean this loops doesn't show jus ONE result! — user10588443
– user10588443, Commented Oct 31, 2018 at 23:14

Geat · Accepted Answer · 2018-10-31 23:14:16Z

1

It's a little difficult to decipher what you're after, but are you looking for something like this?

var array = [12, "Data", true, "S"];
var searchItem = "Data";
var i;
var found = false;

for (i = 0; i < array.length; i++) {
  if (array[i] == searchItem) found = true;
}

console.log(found?'Item Found':'Item Not Found');

answered Oct 31, 2018 at 23:14

Geat

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