how to loop over array of objects and get values

Question

Please read fully. Do not mark it duplicate until you really find it. I have an array of objects like below.

const filterParams = [
      { 'waterfront_type[]': 'Cove' },
      { 'area[]': 'Applehead Island' },
      { 'waterfront_type[]': 'Channel' },
      { 'waterfront_type[]': 'Open Water' },
      { baths: '0 - 14' },
      { price: '0.00 - 9,876,100.00' }
    ];

I need to loop over this and add this to form data. I'm doing like below.

filterParams.map(param => {
      return formData.append(param.key, param.value);
    });

Expected: param.key is waterfront_type[] and param.value is Cove. so internally it should be formData.append('waterfront_type[]', 'Cove');

Getting: both undefined. formData.append(undefined, undefined);

Expected: param.key is waterfront_type[] why would you expect that? — VLAZ
– VLAZ, Commented Oct 25, 2018 at 6:03
And why are you using .map at all, if all you want is to loop through the array? — VLAZ
– VLAZ, Commented Oct 25, 2018 at 6:04
Try using formData.append(Object.keys(param)[0], Object.values(param)[0]) — user3743266
– user3743266, Commented Oct 25, 2018 at 6:07
@user3743266 I don't think that's doing what you think it would be doing. — VLAZ
– VLAZ, Commented Oct 25, 2018 at 6:08

Ori Drori · Accepted Answer · 2018-10-25 10:22:10Z

4

You can use Object.entries(), and array destructuring to get the key, and the value.

Note: the default = [] handles the case of empty objects.

filterParams.map(param => {
  const [[key, value] = []] = Object.entries(param);
  return formData.append(key, value);
});

If you just need to call formData(key, value), and you don't care about the returned values (if any), use Array.forEach() instead of Array.map():

filterParams.forEach(param => {
  const [[key, value] = []] = Object.entries(param);
  formData.append(key, value);
});

edited Oct 25, 2018 at 10:22

answered Oct 25, 2018 at 6:12

Ori Drori

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Comments

Imesha Sudasingha · Accepted Answer · 2018-10-25 06:08:07Z

0

param variable passed to .map function is a javascript object and you cannot access its keys by using just object.key. Instead do:

filterParams.map(param => {
   var keys = Object.keys(param);
   return formData.append(keys[0], param[keys[0]]);
});

Here, we are getting all the keys of the param object and get the first (0th index) as the key you require (assuming that your array have objects with one key).

answered Oct 25, 2018 at 6:08

Imesha Sudasingha

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Comments

Beri · Accepted Answer · 2018-10-25 06:09:26Z

0

So you want to put all dictionary entrySet into a FormData:

filterParams.forEach(param => {
    Object.keys(param).forEach(function(key) {
         let value = param[key];
         formData.append(key, value);
    });      
});

It will produce the output of:

["waterfront_type%5B%5D=Cove",
 "area%5B%5D=Applehead%20Island",
 "waterfront_type%5B%5D=Channel",
 "waterfront_type%5B%5D=Open%20Water",
 "baths=0%20-%2014",
 "price=0.00%20-%209%2C876%2C100.00"]

answered Oct 25, 2018 at 6:09

Beri

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Comments

Parit · Accepted Answer · 2018-10-25 07:26:21Z

-1

you can use javascript filters

 filterParams = filterParams.filter(function(itm){
   Object.keys(itm).forEach(function(key, value){
     return formData.append(key, value);
   })
 })

answered Oct 25, 2018 at 7:26

Parit

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8 Comments

VLAZ Over a year ago

Why use .filter if all you want is to loop through the array?

Parit Over a year ago

looping through the array or using javascript filters i think both should be the same. anyhow you have iterate through that array that does not matter if you are using filter, map or simple loop iteration. iteration complexity would be the same. Thanks

VLAZ Over a year ago

If it doesn't matter, why are there different methods - .filter, .map, .forEach, .some, .every, .find? There would surely need to be a single one if they just go through the array.

Parit Over a year ago

in any PL array iteration is done in O(n) time only. the difference lies in the way we are picking up (search through the element ) that could be in (binary search way, a tree form or a hashing way) in this case search can take O(logn) time or O(1) time but all these works on sorted array, since array of object, are not sorted and to make it sorted you again need quicksort or some other methodologies that itself take O(nlogn) or O(n) time. hence definitely you need to iterate through the array in every possible way whether you are using (filter, map or forEach...etc). i hope you are clear.

VLAZ Over a year ago

But you are specifically suggesting .filter. Why? What's the advantage over any other method? And are you aware of why are there different ones?

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