String replacement array of strings in Scala

Question

I'm confused as to how i can create a new string on the basis of another, replacing some values of the original string,

If i have

Array(easy_id, 1_sum(term_invested_points), 1_sum(std_invested_points), 1_sum(std_used_points), 1_sum(term_used_points), 9_sum(term_invested_points))

and want to produce

Array(easy_id, 1_sum_term_invested_points_, 1_sum_std_invested_points_, 1_sum_std_used_points_, 1_sum_term_used_points_, 9_sum_term_invested_points_)

i.e substitute brackets for underscores in my array.

I have tried

array.columns.map{ case "" => "("; case x => x }

However this just produces the original array, why doesn't it work?

James Whiteley · Accepted Answer · 2018-07-11 08:39:35Z

4

You could do something like this:

val arr = Array(
  "easy_id",
  "1_sum(term_invested_points)",
  "1_sum(std_invested_points)",
  "1_sum(std_used_points)",
  "1_sum(term_used_points)",
  "9_sum(term_invested_points)"
)

arr.map(_.replaceAll("\\(|\\)", "_"))

Map inside the array and replace all opening or closing brackets with underscores (brackets need to be escaped with backslashes as they are Regex special characters).

answered Jul 11, 2018 at 8:39

James Whiteley

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