Clean way to measure multiple code execution times in Python

Question

I want to get the execution time of several portions of my code. Currently I am using time.time() but I feel a bit dumb when writing again and over again code like this:

start = time()
function1(args1)
print("Execution of function1: {}".format(time()-start))

start = time()
function2(args2)
print("Execution of function2: {}".format(time()-start))

start = time()
function3(args3)
print("Execution of function3: {}".format(time()-start))

Please do you know any smarter way to do this? I couldn't find any module that would enable to do things like this (for instance):

chrono("Execution of function1")
function1(args1)

chrono("Execution of function2")
function2(args2)

chrono("Execution of function3")
function3(args3)

sandeep nagendra · Accepted Answer · 2018-06-21 03:52:31Z

3

import time

def timeit(method):
    def timed(*args, **kw):
        ts = time.time()
        result = method(*args, **kw)
        te = time.time()
        print '%r (%r, %r) %2.2f sec' % \
            (method.__name__, args, kw, te-ts)
        return result
    return timed


@timeit
def function1():
    time.sleep(1)
    print 'function1'

>>> function1()
function1
'function1' ((), {}) 1.00 sec

Use this decorator for function definition.

Reference:

https://www.zopyx.com/andreas-jung/contents/a-python-decorator-for-measuring-the-execution-time-of-methods

answered Jun 21, 2018 at 3:52

sandeep nagendra

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Comments

bzier · Accepted Answer · 2018-06-21 03:00:01Z

0

Take a look at the timeit module.

https://docs.python.org/3/library/timeit.html

From that page,

>>> import timeit
>>> timeit.timeit('"-".join(str(n) for n in range(100))', number=10000)
0.3018611848820001
>>> timeit.timeit('"-".join([str(n) for n in range(100)])', number=10000)
0.2727368790656328
>>> timeit.timeit('"-".join(map(str, range(100)))', number=10000)
0.23702679807320237

answered Jun 21, 2018 at 3:00

bzier

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