if (file_exists("displaytab.php")) {
$sys = fopen("displaytab.php", "r+");
system(".\displaytab.php"); }
I've tried to run the script in displaytab.php that I saved in the directory of my local server, I searched for the correct signature of system() and I used it, but it doesn't work. Am I using the wrong command or the right one but in the wrong way?
Wrong command. All you need to do is
include 'displaytab.php';
include includes the specified file at the current point, as if the code was present in the current file. So it gets parsed/executed like the code in the current file (and with the current scope)the php system function accepts a command to be executed you could try :
<?php
$file = 'file.php';
system('php '.$file);
?>
To include php file inside another php file you should use require() or include().
The different between this two functions is if you use require() and the file you invite contain fatal erros will block the script to execute but if you use include() the file execute however if contain erros.
And there is to other functions require_once() and include_once they do the same thing but if you want your file invite one time in php file.
fopenfirst. And how can you tell it isn't executing? What are you expecting when it works?.\displaytab.php? Are you sure the file is actually executable?