Sort Array of Objects by Nested Key Value

Question

I have originalArray that contains objects. How would I go around sorting arrays inventory array by key value short:

var originalArray = [
  {
    name: 'Store1',
    inventory: [
      { name: 'Oranges', qt: { short: 11, long: 3, med: 9 } },
      { name: 'Mango', qt: { short: 3, long: 91, med: 3 } },
      { name: 'Kiwi', qt: { short: 2, long: 91, med: 3 } },
      { name: 'Papaya', qt: { short: 8, long: 91, med: 3 } }
    ]
  },
  {
    name: 'Store2',
    inventory: [
      { name: 'Pizza', qt: { short: 31, long: 11, med: 23 } },
      { name: 'Burger', qt: { short: 1, long: 11, med: 23 } },
      { name: 'IceCream', qt: { short: 111, long: 11, med: 323 } }
    ]
  }
];

Desired output is:

var sorted = [
  {
    name: 'Store1',
    inventory: [
      { name: 'Kiwi', qt: { short: 2, long: 91, med: 3 } },
      { name: 'Mango', qt: { short: 3, long: 91, med: 3 } },
      { name: 'Papaya', qt: { short: 8, long: 91, med: 3 } },
      { name: 'Oranges', qt: { short: 11, long: 3, med: 9 } }
    ]
  },
  {
    name: 'Sotre2',
    inventory: [
      { name: 'Burger', qt: { short: 1, long: 11, med: 23 } },
      { name: 'Pizza', qt: { short: 31, long: 11, med: 23 } },
      { name: 'IceCream', qt: { short: 111, long: 11, med: 323 } }
    ]
  }
];

I don't need anything but inventory array sorted by short value.

All the items of inventory array are sorted in dsc order. Performance is not an issue nor is language spec limit only limitation is that I can not use external libraries.

Is there a sane way of doing this or I need to pluck inventory into intermediary variable sort it there and create new array of objects with inventory sorted.

you could add what you have tried, and what is not working ... — Nina Scholz
– Nina Scholz, Commented Mar 13, 2018 at 16:05
try to implement something by yourself. It's just loop combined with Array.sort — MysterX
– MysterX, Commented Mar 13, 2018 at 16:05
It is really watered down array, I am already 5 layers deep into map and reduce to get that and I can not use intermediary variables nor helpers. Posting whole code would get me nowhere, and besides it was silly mistake on my end. — ukaric
– ukaric, Commented Mar 13, 2018 at 16:12

Igor · Accepted Answer · 2018-03-13 16:07:34Z

9

var originalArray = [
  {
    name: 'Store1',
    inventory: [
      { name: 'Oranges', qt: { short: 11, long: 3, med: 9 } },
      { name: 'Mango', qt: { short: 3, long: 91, med: 3 } },
      { name: 'Kiwi', qt: { short: 2, long: 91, med: 3 } },
      { name: 'Papaya', qt: { short: 8, long: 91, med: 3 } }
    ]
  },
  {
    name: 'Store2',
    inventory: [
      { name: 'Pizza', qt: { short: 31, long: 11, med: 23 } },
      { name: 'Burger', qt: { short: 1, long: 11, med: 23 } },
      { name: 'IceCream', qt: { short: 111, long: 11, med: 323 } }
    ]
  }
];

for (var i = 0; i < originalArray.length; i++) {
  originalArray[i].inventory.sort(function(a, b) { return a.qt.short - b.qt.short; });
}

console.log(originalArray);

answered Mar 13, 2018 at 16:07

Igor

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2 Comments

ukaric Over a year ago

I did try that but I forgot to loop trough each array entry and use it that way. Silly mistake I guess I'm way just tiered.

localhost Over a year ago

If anyone wants to sort on string (name) property then change return statement to return a.name > b.name ? 1 : -1

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