PowerShell How to Pass multiple integer parameters in a function

Question

I am learning PowerShell and I had a question about passing parameters. I wanted to create a function that allows you to pass in 2 integer parameters. It takes the first parameter and 'raises' it to the magnitude of the second number. ie get-power(3,2) would be 9. It appears that when I run this function that it creates an array. How do I either use the values inside the array to complete the function or am I missing a step or concept.

function get-power{
  Param
 (
    [Parameter(Mandatory=$true, Position =0)]
    [int]$arg1,
    [Parameter(Mandatory=$true, Position= 1)]
    [int]$arg2
    )
      [math]::Pow([int]$arg1, [int]$arg2)
}

Actually, it should return a double. You can cast it as in [int] if you want if the answer is not bigger than an int. — Parrish
– Parrish, Commented Oct 3, 2017 at 21:20
You call the function like so: get-power 3 2. Your function works as is. — C. Helling
– C. Helling, Commented Oct 3, 2017 at 21:25
Omgosh, I was trying to return it as get-power(3,2) Thank you so much — Jeffery Bella
– Jeffery Bella, Commented Oct 3, 2017 at 22:00

Esperento57 · Accepted Answer · 2017-10-04 02:29:39Z

3

Just do it:

function get-power([int]$arg1, [int]$arg2)
{
    [math]::Pow([int]$arg1, [int]$arg2)
}


$result=get-power 3 2
$result

answered Oct 4, 2017 at 2:29

Esperento57

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