i have hex list like this ['0x1', '0x3', '0x2', '0x0', '0x0', '0x10', '0x4', '0x0', '0x0', '0xfa', '0x4']
and i intend to send it over USB, so i need to convert into a bytearray, is there a way available in python?
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1@downvoter: It's a valid question, why the downvote?zengr– zengr2017-09-13 07:30:51 +00:00Commented Sep 13, 2017 at 7:30
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2I did't down vote :), May be because of lack of research to ask this question.Rahul K P– Rahul K P2017-09-13 07:32:39 +00:00Commented Sep 13, 2017 at 7:32
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1It is not a duplicate of that question, because he has leading '0x'koalo– koalo2017-09-13 07:35:47 +00:00Commented Sep 13, 2017 at 7:35
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true i have this extra 0x which i am trying to convert to bytes, i tried doing a int conversion and then to bytes, but the solution from @koalo is perfect, marking it as best answerSandeep Shyam– Sandeep Shyam2017-09-15 12:01:00 +00:00Commented Sep 15, 2017 at 12:01
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1 Answer
That can be solved by a simple one line expression
input = ['0x1', '0x3', '0x2', '0x0', '0x0', '0x10', '0x4', '0x0', '0x0', '0xfa', '0x4']
result = bytes([int(x,0) for x in input])
The result is
b'\x01\x03\x02\x00\x00\x10\x04\x00\x00\xfa\x04'
If you do not actually want to have a byte array, but an array of integers, just remove the bytes()
result = [int(x,0) for x in input]
The result is
[1, 3, 2, 0, 0, 16, 4, 0, 0, 250, 4]
1 Comment
Sandeep Shyam
thanks @koalo for your response, one small correction is to use bytearray instead of bytes , i am not sure if its due to my version of python (i am using 2.7), using bytes gives me int array somehow :(