Android 4.4 + Parse.com query array of pointers

Question

It's so wired parse query in array of pointer can't work on 4.4 below and everything working fine for 5 + ,

ParseQuery<ParseObject> firstQuery = new ParseQuery<ParseObject>(CLASSNAME);
    firstQuery.whereEqualTo(COLOUMNNAME1, ParseUser.getCurrentUser());

    ParseQuery<ParseObject> secondQuery = new ParseQuery<ParseObject>(CLASSNAME);
    secondQuery.whereEqualTo(COLOUMNNAME2, ParseUser.getCurrentUser());

    List<ParseQuery<ParseObject>> queries = new ArrayList<ParseQuery<ParseObject>>();
    queries.add(firstQuery);
    queries.add(secondQuery);

    ParseQuery<ParseObject> mainQuery = ParseQuery.or(queries);

Second query is array of parse user pointers.

Note : In Android 5 return all matched data in both. in Android 4.4 return all matched data in first query only.

Did you use parse debug logging to make sure it's going to the same database? — nasch
– nasch, Commented May 9, 2017 at 22:47
@JakeT. first query filter in coloumn of parse user and working for both 4.4 and 5 + — Mohamed Hussien
– Mohamed Hussien, Commented May 10, 2017 at 8:33

Jake T. · Accepted Answer · 2017-05-11 14:30:34Z

1

It seems there's been a fix for this as of 5 days ago, though there isn't additional feedback that it has worked: https://github.com/parse-community/parse-server/issues/175

Make sure you're on the latest parse-server and maybe it'll work.

Beyond that, two solutions are offered: 1) Refactor your code to store arrays of objectIds rather than pointers. This is not broken.

2) Refactor your code to instead of calling whereEqualTo, you call whereContainsAll, and pass a single element array with the pointer you need. This function does not seem broken.

answered May 11, 2017 at 14:30

Jake T.

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1 Comment

Mohamed Hussien Over a year ago

Thank you it's working now after using whereContainsAll

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