Write output of for loop to multiple files with same filename as input file

Question

I have a list of filenames in the file filenames.txt. I am opening all the files one by one, and want to write the result of some operation to a different directory but with the same file name. So far, I tried this, but this won't work. Any help?

with open("/home/morty/filenames.txt","r") as f:
    names = [name.strip() for name in f]

for name in names:
    save=open("/home/morty/dir/%name" %name,"w")
    save.write(---some operation---)

My question is similar to this, but I don't want the files named by count/enumerate. I want the names to be the same as the input file name: Write output of for loop to multiple files

Jean-François Fabre · Accepted Answer · 2017-02-02 10:21:33Z

1

Your format statement is incorrect. It should be "/home/morty/dir/%s" %name

But when you want to join a directory name with a file name, best is to use os.path.join like this:

for name in names:
    with open(os.path.join("/home/morty/dir",name),"w") as save:
       save.write(---some operation---)

(and a with context block to make sure that the file is closed when done)

answered Feb 2, 2017 at 10:21

Jean-François Fabre♦

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