Get file name from File Path in python

Question

This Question Already have a solution but In my case I'm not getting the correct solution where am I getting wrong?

import os,sys
filename = "C:\Users\Dell\Desktop\ProjectShadow\app2\aapp2s.py"
directory, module_name = os.path.split(filename)
module_name = os.path.splitext(module_name)[0]
print(module_name)
print(directory)

Insterd I want

>> 
aapp2s
C:\User\Dell\Desktop

What's Wrong ?

you're missing the raw prefix r"C:\users\.... \a is a special escape sequence. — Jean-François Fabre
– Jean-François Fabre ♦, Commented Jan 19, 2017 at 13:46
Backslashes in string literals should be escaped. e.g. "C:\\Users\\Dell\\Desktop\\ProjectShadow\\app2\\aapp2s.py", or use r prefix, e.g. r"C:\Users\Dell\Desktop\ProjectShadow\app2\aapp2s.py" — khelwood
– khelwood, Commented Jan 19, 2017 at 13:47

dterpas · Accepted Answer · 2017-01-19 13:49:36Z

2

either use r"C:\Users\Dell\Desktop\ProjectShadow\app2\aapp2s.py" or you can double backshlash the whole thing "C:\\Users\\Dell\\Desktop\\ProjectShadow\\app2\\aapp2s.py"

The strange thing you see on your print is the result of the \a escape char

answered Jan 19, 2017 at 13:49

dterpas

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2 Comments

amitnair92 Over a year ago

what if link is stored in a variable ? how do i use regular expression r' ? with variable??

dterpas Over a year ago

@amitnair92 well you can use something like newText = "%r"%textFromVariable

宏杰李 · Accepted Answer · 2017-01-19 14:00:49Z

0

Try pathlib:

from pathlib import PureWindowsPath
filename = r"C:\Users\Dell\Desktop\ProjectShadow\app2\aapp2s.py"
p = PureWindowsPath(filename)
module_name = p.stem
directory = p.parents[2]
print(module_name)
print(directory)

out:

aapp2s
C:\Users\Dell\Desktop

answered Jan 19, 2017 at 14:00

宏杰李

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